Any time the car is driving, the amount of gas is decreasing.
The only time the amount of gas can increase is the short time when
the car is parked at the gas station and gas is being poured into it.
Amanda drover towards the shop, stopped and got gas, then
drove some more. So the amount of gas decreases for a while,
then increases for a short time, then decreases again.
The middle graph is the one doing that.
Answer:
What is angle "Dea"
Step-by-step explanation:
And what is "aeb"
Answer:
Let's solve your system of equations by elimination.
8x+9y=48;12x+5y=21
Steps:
Multiply the first equation by 5,and multiply the second equation by -9.
5(8x+9y=48)
−9(12x+5y=21)
Becomes:
40x+45y=240
−108x−45y=−189
Add these equations to eliminate y:
−68x=51
Then solve−68x=51for x:
−68x
/−68
=
51
/−68 (Divide both sides by -68)
x= −3
/4
Now that we've found x let's plug it back in to solve for y.
Write down an original equation:
8x+9y=48
Substitute
−3
/4
8x+9y=48:
8(
−3
/4
)+9y=48
9y−6=48 (Simplify both sides of the equation)
9y−6+6=48+6 (Add 6 to both sides)
9y=54
9y
/9 = 54
/9 (Divide both sides by 9) y=6
<em><u>Answer: x= −3
/4 and y=6</u></em>
Hope This Helps! Have A Nice Day!!
a) The cost for 10 mile taxi ride is $18
b) The cost for m mile taxi ride is 1.5 m + 3
Step-by-step explanation:
Step 1 :
The fixed charges for the pick up = $3
Charges per mile = $1.50
Let s denote the total miles driven and t be the total cost for the trip
This can be represented by the equation
t = 3 + 1.5s
Step 2:
Distance traveled by Jonathan in his trip = 10 miles
So cost for riding 10 miles is
t = 3 + 1.5(10) = 3 + 15 = $18
The cost for 10 mile taxi ride is $18
Step 3 :
If the distance traveled is m miles, then substituting s = m in the above equation we get the cost as 1.5 m + 3
Step 4 :
Answer :
a) The cost for 10 mile taxi ride is $18
b) The cost for m mile taxi ride is 1.5 m + 3
