Step-by-step explanation:
Using that fact that,
![\cos(u) = \frac{x}{r}](https://tex.z-dn.net/?f=%20%5Ccos%28u%29%20%20%3D%20%20%5Cfrac%7Bx%7D%7Br%7D%20)
and
![{r}^{2} = {x}^{2} + {y}^{2}](https://tex.z-dn.net/?f=%20%7Br%7D%5E%7B2%7D%20%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%20%20%7By%7D%5E%7B2%7D%20)
We need to find sin which that formua is
![\sin(u) = \frac{y}{r}](https://tex.z-dn.net/?f=%20%5Csin%28u%29%20%20%3D%20%20%5Cfrac%7By%7D%7Br%7D%20)
We know what r and x is so we need to find y.
![{8}^{2} = { - 3}^{2} + {y}^{2}](https://tex.z-dn.net/?f=%20%7B8%7D%5E%7B2%7D%20%20%3D%20%20%7B%20-%203%7D%5E%7B2%7D%20%20%2B%20%20%7By%7D%5E%7B2%7D%20)
![64 = 9 + {y}^{2}](https://tex.z-dn.net/?f=64%20%3D%209%20%2B%20%20%7By%7D%5E%7B2%7D%20)
![55 = {y}^{2}](https://tex.z-dn.net/?f=55%20%3D%20%20%7By%7D%5E%7B2%7D%20)
![\sqrt{55} = y](https://tex.z-dn.net/?f=%20%5Csqrt%7B55%7D%20%20%3D%20y)
Sin is positve on the interval pi/2 to pi. so we get
![\sin(u) = \frac{ \sqrt{55} }{8}](https://tex.z-dn.net/?f=%20%5Csin%28u%29%20%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B55%7D%20%7D%7B8%7D%20)
b.
![\tan(u) = \frac{y}{x}](https://tex.z-dn.net/?f=%20%5Ctan%28u%29%20%20%3D%20%20%5Cfrac%7By%7D%7Bx%7D%20)
so
![\tan(u) = - \frac{ \sqrt{55} }{3}](https://tex.z-dn.net/?f=%20%5Ctan%28u%29%20%20%3D%20-%20%20%20%5Cfrac%7B%20%5Csqrt%7B55%7D%20%7D%7B3%7D%20)
c.
![\sec(u) = \frac{r}{ x}](https://tex.z-dn.net/?f=%20%5Csec%28u%29%20%20%3D%20%20%5Cfrac%7Br%7D%7B%20x%7D%20)
![\sec(u) = - \frac{8}{3}](https://tex.z-dn.net/?f=%20%5Csec%28u%29%20%20%3D%20-%20%20%20%5Cfrac%7B8%7D%7B3%7D%20)
d.
![\sin(2u) = 2 \sin(u) \cos(u)](https://tex.z-dn.net/?f=%20%5Csin%282u%29%20%20%3D%202%20%5Csin%28u%29%20%20%5Ccos%28u%29%20)
![2 ( \frac{ \sqrt{55} }{8} )( - \frac{3}{8} ) = \frac{ - 6 \sqrt{55} }{64} = \frac{ - 3 \sqrt{55} }{32}](https://tex.z-dn.net/?f=2%20%28%20%5Cfrac%7B%20%5Csqrt%7B55%7D%20%7D%7B8%7D%20%29%28%20-%20%20%5Cfrac%7B3%7D%7B8%7D%20%29%20%3D%20%20%5Cfrac%7B%20-%206%20%5Csqrt%7B55%7D%20%7D%7B64%7D%20%20%3D%20%20%5Cfrac%7B%20-%203%20%5Csqrt%7B55%7D%20%7D%7B32%7D%20)
e.
![\cos {}^{} (2u) = \cos {}^{2} (u) - \sin {}^{2} (u)](https://tex.z-dn.net/?f=%20%5Ccos%20%7B%7D%5E%7B%7D%20%282u%29%20%20%3D%20%20%5Ccos%20%7B%7D%5E%7B2%7D%20%28u%29%20%20-%20%20%5Csin%20%7B%7D%5E%7B2%7D%20%28u%29%20)
![( \frac{ - 3}{8} ) {}^{2} - ( \frac{ \sqrt{55} }{8} ) {}^{2} = \frac{ - 46}{64} = - \frac{23}{32}](https://tex.z-dn.net/?f=%28%20%5Cfrac%7B%20-%203%7D%7B8%7D%20%29%20%7B%7D%5E%7B2%7D%20%20-%20%28%20%5Cfrac%7B%20%5Csqrt%7B55%7D%20%7D%7B8%7D%20%29%20%7B%7D%5E%7B2%7D%20%20%3D%20%20%5Cfrac%7B%20%20-%2046%7D%7B64%7D%20%20%3D%20%20-%20%20%5Cfrac%7B23%7D%7B32%7D%20)
Answer
Find out the how many cats were at the shelter on Thursday .
To prove
let us assume that the number of cats in the animal shelter be x.
let us assume that the number of dogs in the animal shelter be y.
As given
An animal shelter spends $5.00 per day to care for each cat and $7.00 per day to care for each dog.
Brayden noticed that the shelter spent $193.00 caring for cats and dogs on Thursday.
Than the equation becomes
5x + 7y = 193
Brayden found a record showing that there were a total of 29 cats and dogs on Thursday.
Than the equation becomes
x + y = 29
Than two equation are
5x + 7y = 193 , x + y = 29
Multiply x + y = 29 by 7 and subtrscted from 5x + 7y = 193 .
5x - 7x + 7y - 7y = 193 - 203
5x - 7x = 193 - 203
-2x = -10
![x = \frac{10}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B10%7D%7B2%7D)
x = 5
Therefore the number of cats are 5 on Thursday .
Answer:
I believe that the answer is a
Step-by-step explanation:
tangent is
opposite/adjacent
Answer:
C - x < -6 and x < 2
Step-by-step explanation:
2x ">" -12 and 7x < 14. with negative numbers, the bigger the number the less it is. -12 < -6 because negative numbers work the opposite way that positive numbers do. I hope this helps you!!!!