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3 years ago

At age 16, Estelle weighed 110lbs.

Mathematics

1 answer:

Cloud [144]3 years ago

7 0

Answer:

Her weight is increase by 18 lbs over past five years and the slope is 3.6 lbs per year.

Step-by-step explanation:

Given information: Estelle weight is

At age 16 = 110 lbs

At age 21 = 128 ibs

Increase in her weight over the past 5 years is the difference of weight at age 21 and at age 16.

Increase in her weight over the past 5 years = 128 - 110 = 18

Her weight is increase by 18 lbs over past five years.

Let x=age and y=weight, then the weight function passes through the points (16,110) and (21,128).

If a line passes through two points $(x_1,y_1)$ and $(x_2,y_2)$ , then the slope of the line is

$m=\frac{y_2-y_1}{x_2-x_1}$

Using the above formula we get

$m=\frac{128-110}{21-16}$

$m=\frac{18}{5}$

$m=3.6$

Therefore the slope is 3.6 lbs per year.

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Cost of each bags of flour = $2.50

Cost of each bags of butter = $3.75

Solution:

Let f be the bags of flour and b be the pounds of butter.

Cost of 20 bags of flour 16 pound of butter = 110

⇒ 20f + 16b = 110 -------------------- (1)

Cost of 30 bags of flour 12 pound of butter = 120

⇒ 30f + 12b = 120 -------------------- (2)

Equation (1) and (2) are the system of equations.

(2) ⇒ 30f + 12b = 120

Subtract 30f from both sides.

⇒ 12b = 120 – 30f

Divide by 12 on both sides.

$$\Rightarrow b =\frac{120-30f}{12}$ -------------------- (3)

Substitute (3) in (1).

$$20f+16\left(\frac{120-30f}{12}\right)=110$

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Subtract 160 from both sides.

$$-20f=-50$

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