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n200080 [17]
3 years ago
14

If a cube has a volume of 64 cubic inches, what is the area of the base of the cube?

Mathematics
1 answer:
Korolek [52]3 years ago
6 0

Answer:

A = 16 cubic inches

Explanation:

If the volume is 64 cubic inches, that means each side (length, width, and height) are 4 inches each. This makes the area (l × w) is 16 cubic inches

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Answer:

d=28.28

Step-by-step explanation:

To calculate the lenght of the diagonal d across the square, we can assume that the square it is compound of two right triangles. So, we can resolve this exercise using The Pythagorean Theorem.

<em>The Pythagorean theorem</em> states that in every right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the respective lengths of the legs. It is the best-known proposition among those that have their own name in mathematics.

If in a right triangle there are legs of length a and b, and the measure of the hypotenuse is c, then the following relation is fulfilled:

a^{2} +b^{2} =c^{2} a is the height, b is the base, and c is  

the hypotenuse.

To obtain the value of the hypotenuse

c= \sqrt{a^{2} +b^{2} }

To find the value of the lenght of the diagonal d across the square, we have:

d=\sqrt{a^{2} +b^{2} } Where a = b = 20

Substituting the values

d=\sqrt{(20)^{2} +(20)^{2} }\\d=\sqrt{400+400} =\sqrt{800} \\d=28.284

Round the answer to 2 decimal places

d=28.28

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Step-by-step explanation:

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