3 years ago

NEED HELP FAST PLEASE.

Mathematics

1 answer:

My name is Ann [436]3 years ago

5 0

I'm pretty sure its A but it could be B

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I have 1,141 point i thought i might share them you here you go

zaharov [31]

Answer:

Thank you, person.

I hope this is good enough:

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3 years ago

A square pyramid has side lengths each measuring 8 centimeters. The height of the pyramid is 3 centimeters,

tino4ka555 [31]

You answer would be 80 cm^2

7 0

3 years ago

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

7 0

3 years ago

Jada has read 3/5 of a book. She has read 75 pages so far. How many pages are in the whole book?

saveliy_v [14]

Answer:

125 pages

Step-by-step explanation:

we can use a proportion

3/5=75/x

multiply cross so 75×5 and 3×X

375=3x

÷3. ÷3

x=125

check

75/125=simplified is 3/5

7 0

3 years ago

NEED HELP!!!!!!!!!!!!!!!

musickatia [10]

It's D, it's the only one where it has a -6 at the end other than A, but if you look at the A when distributed there isn't a 23x<span />

3 0

3 years ago

Read 2 more answers