Part 1We are given

. This can be rewritten as

.
Therefore, a=1, b=-18, c=0.
Using the quadratic formula

The values of x are
Part 2Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a
quadratic function. Part 3.The first equation is

.
The second equation is

.
We have

Factoring, we have

Equating both factors to zero.

When the value of x is 6, the value of y is

When the value of x is -3, the value of y is

Therefore, the solutions are (6,38) or (-3,11)
Using row 4:
<span>coefficients are: 1, 4, 6, 4, 1 </span>
<span>a^4 + a^3b + a^2b^2 + ab^3 + b^4 </span>
<span>Now adding the coefficients: </span>
<span>1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + 1b^4 </span>
<span>Substitute a and b: </span>
<span>a = 4x </span>
<span>
b = -3y </span>
<span>1(4x)^4 + 4(4x)^3(-3y) + 6(4x)^2(-3y)^2 + 4(4x)(-3y)^3 + 1(-3y)^4 </span>
<span>Now simplify the above: </span>
<span>256x^4 - 768x^3y + 864x^2y^2 - 432xy^3 + 81y^4 </span>
Answer:
30
Step-by-step explanation:
I think it is not because it’s also not proportional and they are basically identical except for what b is equal to