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Nastasia [14]
3 years ago
6

There are a combined total of 60 marbles in the jar consisting of red, green, blue and white marbles. The following is the propo

rtions of the marbles: One third of the marbles are red Half the marbles are blue The remaining 1/6 is divided up evenly between the green and white marbles Determine how many marbles of each color are in the jar.
Mathematics
2 answers:
lilavasa [31]3 years ago
6 0
Blue marbles: 1/2 of 60 is 30 blue
Red marbles: One third of 60 is 20 red
Green and white marbles: 1/6 of 60 is 10, so 10/2 is 5 green and 5 white.

To check the math, 30+20+5+5 = 60 total.

Molodets [167]3 years ago
5 0
Red=20 (1/3 x 60=20)
Blue=30 (1/2 x 60=30)
Green=5 (1/12 x 60=5)
White=5 (1x12 x 60=5)
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oee [108]
Hope this helps.......

7 0
3 years ago
1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n
Andrew [12]
Part 1
We are given x^2-21x=-4x. This can be rewritten as x^2-18x=0.
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
     x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}
     x=\frac{18\pm 18}{2}

The values of x are
     x_1=\frac{18-18}{2}=0
     x_2=\frac{18+18}{2}=18

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function. 

Part 3.
The first equation is y=x^2+2.
The second equation is y=3x+20.

We have 
     x^2+2=3x+20
     x^2-3x-18=0
Factoring, we have 
     \left(x-6\right)\left(x+3\right)=0
Equating both factors to zero.
     x_1-6=0\rightarrow x_1=6
     x_2+3=0\rightarrow x_2=-3

When the value of x is 6, the value of y is 
     y=3\left(6\right)+20=38

When the value of x is -3, the value of y is 
     y=3\left(-3\right)+20=11

Therefore, the solutions are (6,38) or (-3,11)
7 0
2 years ago
Expand (4x-3y)^4 using pascal's triangle ...?
jenyasd209 [6]
Using row 4: 

<span>coefficients are: 1, 4, 6, 4, 1 </span>

<span>a^4 + a^3b + a^2b^2 + ab^3 + b^4 </span>

<span>Now adding the coefficients: </span>

<span>1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + 1b^4 </span>

<span>Substitute a and b: </span>

<span>a = 4x </span>
<span>
b = -3y </span>

<span>1(4x)^4 + 4(4x)^3(-3y) + 6(4x)^2(-3y)^2 + 4(4x)(-3y)^3 + 1(-3y)^4 </span>

<span>Now simplify the above: </span>

<span>256x^4 - 768x^3y + 864x^2y^2 - 432xy^3 + 81y^4 </span>
8 0
3 years ago
Please see image below
exis [7]

Answer:

30

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please Help!
Makovka662 [10]
I think it is not because it’s also not proportional and they are basically identical except for what b is equal to
5 0
2 years ago
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