You didn’t specify a method, so i guess all of the above
Answer:
A (DE = GF)
Step-by-step explanation:
In a isosceles trapezoid, one pair of segments are parallel, and another pair are equivalent in length.
The only choice that fits this criteria is A, where DE equals GF.
Answer:
I don't know the answer. .
Answer:
This cannot be answered without more information.
Step-by-step explanation:
Answer:
71.6 degrees
Step-by-step explanation:
Given the vectors
u= <8,4> v = <9.-9> (5 points)
u*v = (8, 4)*(9, -9)
u*v = 8(9)+(4)(-9)
u*v = 72 - 36
u*v = 36
|u| = √8²+4²
|u| = √64+16
|u| = √80
|v| = √9²+9²
|v| = √81+81
|v| = √162
Using the formula
u*v = ||u||v| cos theta
36 = √80(√162)cos theta
36 = √12960 cos theta
cos theta = 36/√12960
cos theta = 36/113.8
cos theta = 0.3162
theta = arccos(0.3162)
theta = 71.56 degrees
Hence the angle between the given vectors to the nearest tenth of a
degree is 71.6 degrees
