Answer:
The new pressure is 4.27 pounds
Step-by-step explanation:
In this question, we have the volume varying inversely as the pressure;
Firstly, let's say the volume is V and the pressure is P
Mathematically;
V ∝ 1/P
Let us insert a constant of proportionality K
⇒ VP = K
Let's calculate the value of K
K = 32
× 8 = 256 
Now in the second scenario, pressure is unknown but we know the volume to be 60
Recalling; VP = K
P = K/V = 256
/60
= 4.27 pounds
Answer:
The numerical limits for a B grade is between 81 and 89.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

B: Scores below the top 13% and above the bottom 56%
Below the top 13%:
Below the 100-13 = 87th percentile. So below the value of X when Z has a pvalue of 0.87. So below X when Z = 1.127. So




Above the bottom 56:
Above the 56th percentile, so above the value of X when Z has a pvalue of 0.56. So above X when Z = 0.15. So




The numerical limits for a B grade is between 81 and 89.
Step-by-step explanation:
5x^2+2x=1
5x^2+2x-1=0
x=-b+/-√b^2-4ac÷2a
x=-2+/-√-2^2-(4×5×-1)÷2×5
x=-2+/+√4--20÷10
x=-2+/-√24÷10
x=-2+√24÷10 or -2-√24÷10
x=-2+4.9÷10 or -2-4.9÷10
x=2.9÷10 or -6.9÷10
x=0.29 or -0.69
Answer:
17
Step-by-step explanation:
Substitute "x" for "5" in the equation
3(5) + 2
15 + 2
17