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just olya [345]
3 years ago
5

The sum of a number divided by 5 and 12 is 16. What is the number?

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
8 0

x/5)+12=16

x/5=4

x=20

Hope this helps! Have a nice day!

tankabanditka [31]3 years ago
8 0

SHEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEESH

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The Patronete Winery's tastiest wine must have a 12% alcohol content. How many gallons of wine with a 9% alcohol content must be
erik [133]

Answer: 3000 gallon

Step-by-step explanation:

Here, The total quantity of 15% alcohol content = 3000 gallon

And, in which quantity of alcohol = 15% of 3000 gallon = 450 gallon.

Let the total quantity of 9% alcohol content  = x

In which quantity of alcohol = 9% of x gallon= 9x/100 gallon

Now, according to the question,  The wine with a 9% alcohol content will be mixed with 3,000 gallons of wine with a 15% alcohol content in order to achieve the desired 12% alcohol content.

Thus, the total quantity of mixture of 12% alcohol content = The total quantity of 15% alcohol content + total quantity of 9% alcohol content

= 3000 + x

In which quantity of alcohol = 12 % of ( 3000+x) = (360 + 12x/100) gallon ---(1)

But, the quantity of alcohol in 12 % of alcohol content = quantity of alcohol in 15% of alcohol content +  quantity of alcohol in 9% of alcohol content

The quantity of alcohol in 12 % of alcohol content = (450 + 9x/100) gallon ---(2)

On equating equation (1) and (2)

We get, 360 + 12x/100 = 450 + 9x/100

⇒ 3x/100 = 90

⇒ x = 3000

Therefore, The total quantity of the mixture of 9% alcohol content = 3000


6 0
4 years ago
Use the power series representation of f(x)=<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B1-5x%7D%20" id="TexFormula1" t
Sergeu [11.5K]
For |5x|, we have

\dfrac1{1-5x}=\displaystyle\sum_{n\ge0}(5x)^n

and so

g(x)=\dfrac{15}{1-5x}=15\displaystyle\sum_{n\ge0}(5x)^n=3\sum_{n\ge0}5^{n+1}x^n

which is, again, only valid for |5x|.
4 0
3 years ago
What is the formula for the nth term of the given sequence 100, 20, 4, …
Naily [24]

Answer:

a_n=100 \left(\dfrac15\right)^{n-1}

Step-by-step explanation:

General equation of geometric sequence:  a_n=ar^{n-1}

Given:

  • a₁ = 100
  • a₂ = 20
  • a₃ = 4

\implies a_1=a=100

\implies a_2=100 \cdot r=20

\implies a_3=100 \cdot r^2=4

Common ratio:

r=\dfrac{a_3}{a_2}=\dfrac{4}{20}=\dfrac15

Therefore:

a_n=100 \left(\dfrac15\right)^{n-1}

6 0
2 years ago
If x an integer and 2x +8 &lt;22 and 3x &gt;9, how many possible values of x are there?
koban [17]

Answer:

3 values

Step-by-step explanation:

2x +8 <22 and 3x >9

Solve the two inequalities separately and then put them back together

2x +8 <22

Subtract 8 from each side

2x +8-8 <22 -8

2x < 14

Divide by 2

2x/2 < 14/2

x < 7

Then solve the second inequality

3x>9

Divide by 3

3x/3>9/3

x >3

Putting them back together

x>3 and x < 7

Since it has to be an integer

4,5,6  are possible choices

3 values

5 0
3 years ago
Read 2 more answers
A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th
umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, <em>p</em> = 0.09.

An item is defective irrespective of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 9 and <em>p</em> = 0.09.

The repair cost of the item is given by:

C=3X^{2}+X+2

Compute the expected cost of repair as follows:

E(C)=E(3X^{2}+X+2)

        =3E(X^{2})+E(X)+2

Compute the expected value of <em>X</em> as follows:

E(X)=np

         =4\times 0.09\\=0.36

The expected value of <em>X</em> is 0.36.

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)

         =4\times 0.09\times 0.91\\=0.3276\\

The variance of <em>X</em> is 0.3276.

The variance can also be computed using the formula:

V(X)=E(Y^{2})-(E(Y))^{2}

Then the formula of E(Y^{2}) is:

E(Y^{2})=V(X)+(E(Y))^{2}

Compute the value of E(Y^{2}) as follows:

E(Y^{2})=V(X)+(E(Y))^{2}

          =0.3276+(0.36)^{2}\\=0.4572

The expected repair cost is:

E(C)=3E(X^{2})+E(X)+2

         =(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73

Thus, the expected repair cost is $3.73.

4 0
3 years ago
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