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asambeis [7]
2 years ago
7

Can y’all help me plz?

Mathematics
1 answer:
gulaghasi [49]2 years ago
3 0

Answer:

13

Step-by-step explanation:

Pythagreom Therom:

a^2+b^2=c^2

12^2+5^2=c^2

144+25=c^2

169=c^2

c=13

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Answer:

32 feet high

Step-by-step explanation:

7 0
2 years ago
The graph shows the amount of money paid when purchasing bags of peanuts at the zoo:
abruzzese [7]

Answer:

dive the cost by the number of bags for each dot:

4 / 1 = 4

8 / 2 = 4

12 / 3 = 4

This means each bag cost $4

The equation would be Y = 4X, because you would multiply each bag bought (X) by $4 to get the total cost (Y).

Step-by-step explanation:

BRAINLYIS TPLS

7 0
3 years ago
State the domain of the numbers displayed in column x and column y. x y
ella [17]

We can not really tell in this question as you dont know the equation that is being used for the domain and range relationship but overall one should know that:

The set of values of the independent variable(s) for which a function or relation is defined as the domain of a function. Typically, this is the set of x-values that give rise to real y-values.

The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually), after we have substituted the domain.


5 0
3 years ago
Rewrite using positive exponents 
Oxana [17]

Answer:

Your selection is appropriate

Step-by-step explanation:

A negative exponent in the numerator is equivalent to a positive exponent in the denominator, and vice versa.

... a⁻² = 1/a²

____

2⁴ multiplies the variable expression no matter which way it is written.

4 0
3 years ago
From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
1 year ago
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