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2 years ago

12

10. A soccer team is having a fundraiser by selling raffle tickets. Each ticket costs $2. For every 3 tickets

2 answers:

sergejj [24]2 years ago

8 0

Answer:

B

Step-by-step explanation:

2 over 3 tickets subtract the 1 dollar discount

-Dominant- [34]2 years ago

8 0

The answer is B.

I hope this helped! And I might be wrong, just saying lol

I don't think I am though...

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Solve the system of equations using substitution and Elimination

juin [17]

<h2>Greetings!</h2>

Answer:

y = $\frac{-18}{7}$ and x = $\frac{50}{7}$

Step-by-step explanation:

To solve simultaneous equations, you need to have the number in front of both x's or y's the same. (signs doesn't matter)

To get -x to -10x we simply need to multiply the first equation by 10:

-x * 10 = -10x

-9y * 10 = -90y

16 * 10 = 160

-10x - 90y = 160

Now we can add the two equations:

-10x + 10x = 0

-90y + 20y = -70y

160 + 20 = 180

-70y = 180

70y = -180

7y = -18

y = $\frac{-18}{7}$

Now plug $\frac{-18}{7}$ into the second equation:

10x + 20( $\frac{-18}{7}$ ) = 20

10x - $\frac{360}{7}$ = 20

Move the $\frac{360}{7}$ over to the other side, making it a positive:

10x = 20 + $\frac{360}{7}$

10x = $\frac{500}{7}$

Divide both sides by 10:

x = $\frac{50}{7}$

So y = $\frac{-18}{7}$ and x = $\frac{50}{7}$

<h2>Hope this helps!</h2>

5 0

2 years ago

Generate the nest three terms of each arithmetic sequence shown below.

o-na [289]

Answer:

A)2,6,10

B)2,-6,-18

C)-1,-3,-5

Step-by-step explanation:

<u>A)a1=-2 and d=4</u>

We know that the arithmetic sequence formula is

$a_{n}=a_{1}+(n-1)d$

Now

$a_{2}=a_{1}+(2-1)d$

$a_{2}=a_{1}+(1)d$

Substituting the given value we get

$a_{2}= -2+(1)4$

$a_{2}= -2+4$

$a_{2}= 2$

------------------------------------------

Similarly

$a_{3}=a_{1}+(3-1)d$

$a_{3}=a_{1}+(2)d$

Substituting the given value we get

$a_{3}= -2+(2)4$

$a_{3}= -2+8$

$a_{3}= 6$

-------------------------------------------------

$a_{4}=a_{1}+(4-1)d$

$a_{4}=a_{1}+(3)d$

Substituting the given value we get

$a_{4}= -2+(3)4$

$a_{4}= -2+16$

$a_{4}= 10$

-------------------------------------------------------------------------------------------

<u>B</u><u> $a_n=a_{(n-1)}-8$ with $a_1=10$ </u>

$a_2=a_{(2-1)}-8$

$a_2=a_{1}-8$

Substituting the given value

$a_2= 10-8$

$a_2=2$

---------------------------------------------------------------------

$a_3=a_{(3-1)}-8$

$a_3=a_{2}-8$

Substituting the value

$a_3=2-8$

$a_3= -6$

---------------------------------------------------------------------

$a_4=a_{(4-1)}-8$

$a_4=a_{3}-8$

Substituting the value

$a_4= -6-8$

$a_4= -14$

-------------------------------------------------------------------------------------------

<u>C) $a_1=3, a_2=1$ </u>

Here the difference is -2

the arithmetic sequence formula is

$a_{n}=a_{1}+(n-1)d$

Now

$a_{3}=a_{1}+(3-1)d$

$a_{3}=a_{1}+(2)d$

Substituting the value we get

$a_{3}= 3+(2)-2$

$a_{3}= 3-4$

$a_{3}= -1$

------------------------------------------------------------------------------

$a_{4}=a_{1}+(4-1)d$

$a_{4}=a_{1}+(3)d$

Substituting the value we get

$a_{4}= 3+(3)-2$

$a_{4}= 3-6$

$a_{4}= -3$

----------------------------------------------------------------------------------

$a_{5}=a_{1}+(5-1)d$

$a_{5}=a_{1}+(4)d$

Substituting the value we get

$a_{5}= 3+(4)-2$

$a_{5}= 3-8$

$a_{5}= -5$

4 0

2 years ago

Graph the numbers that are solutions to both inequalities.

nadya68 [22]

Answer:

p ∈ [5 , 6)

Step-by-step explanation:

p + 6 ≥ 11

⇒ p ≥ 11 - 6

⇒ p ≥ 5

⇒ p ∈ [5 , +∞)

3p < 18

⇒ p < 18/3

⇒ p < 6

⇒ p ∈ (-∞ , 6)

Then

p the solution to both equations verify:

p ∈ (-∞ , 6) ∩ [5 , +∞)

Conclusion :

p ∈ [5 , 6)

3 0

1 year ago

It takes 4 1/2 cups of cherries to make a cherry pie. Russell wants to make 4 cherry pies. How many cups of cherries will Russel

atroni [7]

Answer:

18 cups.

Step-by-step explanation:

Multiply 4.5 by 4.

3 0

2 years ago

Write the fractions in order starting with the smallest 9/8 , 5/4 , 19/16, 3/2.

Kipish [7]

Answer:

9/18, 19/16, 5/4, 3/2

Step-by-step explanation:

3 0

2 years ago