LT 3.3 (I can use the Pythagorean Theorem and relationships with special right to
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is in quadrant I, so
.
is in quadrant II, so
.
Recall that for any angle ,
Then with the conditions determined above, we get
and
Now recall the compound angle formulas:
as well as the definition of tangent:
Then
1.
2.
3.
4.
5.
6.
7. A bit more work required here. Recall the half-angle identities:
Because is in quadrant II, we know that
is in quadrant I. Specifically, we know
, so
. In this quadrant, we have
, so
8.
