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Ipatiy [6.2K]
3 years ago
6

Write the equation of the vertical line that passes through the point (−2, 10). remember to enter your answer as an equation.

Mathematics
1 answer:
posledela3 years ago
5 0
Remark
All vertical lines are of the form x = a. The y value only places where the point is on the grid. 

For this particular question the x value of the point is where the vertical line is. At x = -2 draw a vertical line. The graph shows what this looks like.

The graph (x = - 2) is in red.

The point (-2,10) is green.
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PLEASE HELP FAST!!!
grigory [225]

Answer:

x = 9

Step-by-step explanation:

Since the figures are similar then the ratios of corresponding sides are equal, that is

\frac{x-1}{6} = \frac{16}{12} ( cross- multiply )

12(x - 1) = 96 ( divide both sides by 12 )

x - 1 - 8 ( add 1 to both sides )

x = 9

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2 years ago
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Madeline needs to find the slope of the line that passes through the points (9, 12) and (7, 4). She sets up the following work:
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Answer:

No

Step-by-step explanation:

She has everything correct but one thing. In order to have her answer correct, she must put the 9 in front of the 7 because the bigger number needs to go in front.

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3 years ago
If you decided to build a ramp using the 1:16 slope - ratio requirement , what would be the length of the diagonal portion of th
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Vicky reads at a constant rate. She can read 5 pages in 9 minutes. Write an equation to represent her constant rate
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3 years ago
Given: △ACM, m∠C=90°, CP ⊥ AM
larisa86 [58]

Answer:  The answer is 3\dfrac{4}{7}.

Step-by-step explanation:  Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.

Now,

AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)

Comparing equations (A) and (B), we have

5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.

Thus,

AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.

8 0
3 years ago
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