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DIA [1.3K]
3 years ago
9

3(-1 - x) < -20 - 3x on a number line

Mathematics
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

- 3 - 3x \:  <  \:  - 20 - 3  \\  - 3x <  - 20 - 3 + 3 \\  - 3x <  - 20 \\ x >  - 20 \div 3

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If you popped 3 bags of popcorn in 15 min how many bags did you pop per min
Agata [3.3K]
1 bag per 5 minutes. If you divide 15(total amount of min) by 3(bags of popcorn you popped) you will see you popped 1 bag per 5 minutes. Now its say per minutes, then, you will have to say 1/5 bag per minutes.
3 0
3 years ago
Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol
aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

P(A\cap B)=P(A)\times P(B)

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0
3 years ago
Find the roots. 2x 2 + 7x - 15 =0
Reika [66]
So you always want to pull out the gcf first but since there isn't one, we can move on.
so we can make an acb chart which is multiplying the a value and the c value and find factors that of that product that will equal the b value.
a value is 2
c value is -15
b value is 7
-30 factors to equal 7 = 10, -3
10 - 3 = 7
so the factors 10 and -3 work. 
so now you make 2 separate parenthesis with one of the factors and one x. and it should be set equal to 0.
(x+10)(x-3) = 0
now solve for x in each separate parenthesis. 
x = -10 
x = 3
those r the roots
hope this helps
4 0
3 years ago
Read 2 more answers
In Panama City in January high tide was at midnight. The water level at high tide
Ivanshal [37]
The water levels at high tide was 9 feet and 1 foot at low tide
7 0
2 years ago
Pls help if you actually can
Setler79 [48]

The triangles that are similar would be ΔGCB and ΔPEB  due to Angle, Angle, Angle similarity theorem.

<h3>How to identify similar triangles?</h3>

From the image attached, we see that we are given the Parallelogram GRPC. Thus;

A.  The triangles that are similar would be ΔGCB and ΔPEB  due to Angle, Angle, Angle similarity theorem.

B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;

∠CGB ≅ ∠PEB  (Alternate Interior Angles)

∠BPE ≅ ∠BCG  (Alternate Interior Angles)

∠GBC ≅ ∠EBP  (Vertical Angles)

C.  To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;

225/325 = PE/375  

PE = 260 ft

BE/425 = 225/325  

BE = 294 ft

Read more about Similar Triangles at; brainly.com/question/14285697

#SPJ1

5 0
1 year ago
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