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deff fn [24]
3 years ago
11

What is the answer for this equation : 11p-4= 6p + 1

Mathematics
1 answer:
vova2212 [387]3 years ago
4 0
11p-4=6p+1\ \ \ \ \ |combine\ like\ terms\\\\11p-6p=1+4\ \ \ \ |simplify\\\\5p=5\ \ \ \ \ |:5\\\\p=1
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2. How many 4-digit even numbers greater then 4,999 can be made(using the digits 0-9?
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Answer:

For each choice of the first two digits you have 10 choices for the third digit. Thus you have 10x10x10 = 1000 choices for the first three digits. Finally you have 10 choices for the fourth digit and thus there are 10x10x10x10 = 10 000 possible 4 digit combinations from 0-9.

I hope that helps! :)

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87 to the nearest 10
Alex787 [66]

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Does this graph represent a function why or why not​
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4 years ago
Consider a triangle ABC like the one below. Suppose that =A110°, =b25, and =c4. (The figure is not drawn to scale.) Solve the tr
tamaranim1 [39]

Side a, angle B and angle C of triangle ABC are 26.6 units, 61.9 degrees and 8.1 degrees respectively.

<h3>What is the value of the missing angles and side?</h3>

Given that;

  • Angle A = 110°
  • Side b = 25
  • side c = 4
  • side a = ?
  • Angle B = ?
  • Angle C = ?

First we determine the length of side a

a = \sqrt{b^2-c^2-2bc*cos(A)}

We substitute our values into the above equationa = \sqrt{25^2-4^2-(2*25*4*cos(110)}\\\\a = 26.6

Side a has a length of 26.6 units.

B = cos^{-1}(\frac{a^2+c^2-b^2}{2ac}) \\\\B = cos^{-1}(\frac{26.63464^2+4^2-25^2}{2*26.63464*4}) \\\\B = 61.9

Angle B is 61.9 degrees.

C = cos^{-1}(\frac{a^2+b^2-c^2}{2ab} )\\\\C = cos^{-1}(\frac{26.63464^2+25^2-4^2}{2*26.63464*25} )\\\\C =8.1

Angle C is 8.1 degrees.

Therefore, side a, angle b and angle c of the triangle ABC are 26.6 units, 61.9 degrees and 8.1 degrees respectively.

Learn more about triangles here: brainly.com/question/14882091

#SPJ1

5 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5
CaHeK987 [17]

the heck (keystrokes keystrokes)

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