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ahrayia [7]
3 years ago
13

LONG DISTANCE For Meg’s long-distance calling plan, the monthly cost C in dollars is given by the linear function C(t) = 6 + 0.0

5t, where t is the number of minutes talked.
a. What is the total cost of talking 8 hours? of talking 20 hours?
b. What is the effective cost per minute (the total cost divided by the number of minutes talked) of talking 8 hours? of talking 20 hours?

I really need help
Mathematics
1 answer:
Neko [114]3 years ago
5 0

Answer:

Step-by-step explanation:

The monthly cost is C(t) = 6 + 0.05t, where t is the number of minutes talked.

Talking for 8 hours would cost C(t) = 6 + 0.05(8), or $6.40;

Talking for 20 hours would cost C(20) = 6 + 0.05(20), or $7.00.

The effective cost per minute in the first case is $6.40/8 min = $0.80/min, and that in the second case is $7.00/20 min = $0.35/min

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Answer:

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Step-by-step explanation:

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base =x

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If 1 yard = 3 feet and 1 mile = 5,280 feet, how many yards are there in 2 miles? 2,640 yards 3,520 yards 10,560 yards 31,680 yar
fiasKO [112]

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3 years ago
IM USING 20 POINTS FOR THIS PLS HELP AND SHOW WORK
emmasim [6.3K]

Answer:

the object is in the air on the time interval (0.24 sec, 6.51 sec)

Step-by-step explanation:

The object is 'in the air' for all t such that h> 0.  We need to find the roots of h = -16t^2 + 108t - 25 = 0.  From the graph we see that both t values are positive.  Once we find them, we subtract the smaller t from the larger t, which results in the length of time the object is in the air.

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