<u>Answer:</u>
Standard form of a line passing through (-2, 4) and having slope of -1/7 is x + 7y = 26
<u>Solution:</u>
Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7
Standard form of line passing through point ( a , b ) and having slope m is given by
(y – b) = m ( x – a) --------(1)
In our case given point is ( -2 , 4 ) and slope is -1/7 that means
a = -2 , b = 4 , m = -(1/7)
On substituting given value of a , b and m is equation (1) we get
=> 7( y - 4 ) = -x – 2
=> 7y + x = -2 + 28
=> x + 7y = 26
Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26
Answer:
terrence will have to play 2900
Step-by-step explanation:
80% * 14500
14500-11600
2900
Answer:
(1,-2)
(0,-3)
(-3,0)
Step-by-step explanation:
each point on the line -x+y=-3
Answer:
C
Step-by-step explanation:
We can use the factored form of the quadratic equation, given by:
Where <em>a</em> is the leading coefficient and <em>p</em> and <em>q</em> are the zeros.
We have zeros <em>x</em> = -2 and <em>x</em> = 3. So, let <em>p</em> = -2 and <em>q</em> = 3:
Next, we are given that our <em>y-</em>intercept is (0, -30).
In other words, when <em>x</em> = 0, <em>y</em> = -30. So:
Solve for <em>a:</em>
<em />
<em />
<em />
Hence, our factored equation is:
For the standard form, expand:
Simplify:
Distribute:
Our answer is C.
