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kifflom [539]
3 years ago
9

Winning the jackpot in a particular lottery requires that you select the correct five numbers between 1 and 34 ​and, in a separa

te​ drawing, you must also select the correct single number between 1 and 37. Find the probability of winning the jackpot.
Mathematics
1 answer:
Marina CMI [18]3 years ago
6 0
<h3>The probability of winning the lottery is \frac{1}{10,295,472}</h3>

Step-by-step explanation:

Here, the total numbers in the jackpot = 1 to 34

Now, the number that needed to be drawn = 5

The number of ways , 5 number can be drawn from total 34 numbers :

^{34} C _5 =   \frac{34!}{5!(34-5)!}    = 278,256

Also, in separate draw, the correct number drawn  = 1

So, the number of ways that can be done  =  30 C 5 x  37  

= 278,256 x 37    = 10,295,472

Now, P(win)   =  \frac{\textrm{Total favorable attempts}}{\textrm{Total attempts}}  = \frac{1}{10,295,472}

Hence, the probability of winning the lottery is \frac{1}{10,295,472}

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Bowl A contains 6 apples and 3 mangoes this can be written as, Bowl B contain 8 apples and 2 mangoes this can be written as. Wha
Andrew [12]

Answer:

Bowl B contains 2 apples more than Bowl A and Bowl A contains 1 mango more than Bowl B.

Step-by-step explanation:

Number of apples in Bowl A = 6

Number of mangoes in Bowl B = 8

Difference in apples = 8 - 6 = 2

So, Bowl B contains 2 apples more than Bowl A.

Number of mangoes in Bowl A = 3

Number of mangoes in Bowl B =2

Difference in mangoes = 3 - 2 = 1

So, Bowl A contains 1 mango more than Bowl B.

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3 years ago
There are 4 cups in a quart and 4 quarts in a gallon how many cups in a 5 gallon jug of water
Marysya12 [62]
80 cups in a 5 gallon jug of water.

1 quart has 4 cups
1 gallon has 4 quarts
1 gallon = 4 quarts * 4 cups = 16 cups

5 gallons = has 80 cups of water.

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6 0
3 years ago
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A manufacturing company produces 3 different products A, B, and C. Three types of components, i.e., X, Y, and Z, are used in the
Murljashka [212]

Answer:

Step-by-step explanation:

Using the Excel Formula:

Decision    Variable        Constraint              Constraint

A                     65                          65                         100

B                     80                          80                         80

C                     90                         90                          90

                      14100                    300                        300

= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90

Now, we have:

Suppose A, B, C represent the number of units for production A, B, C which is being manufactured

                             A              B                  C                Unit price

Need of X          2                 1                   1                     $20

Need of Y           2                3                  2                    $30

Need of Z           2                2                  3                    $25

Price of  

manufac -      $200          $240            $220      

turing

Now,  for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.  

Thus, the cost or unit of manufacturing of A is:

$20 (2) + $30(2) + $25(2)

$(40 + 60 + 50)

= $150

Also, the market price of A = $200

So, profit = $200 - $150 = $50/ unit of A

Again;

For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.

So, total cost of manufacturing a unit of B is:

= $20(1) + $30(3) + $25(2)

= $(20 + 90+50)

= $160

And the market price of B = $240

Thus, profit = $240- $160  

profit = $80

For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:

SO, the total cost of manufacturing a unit of C is:

= $20 (1) + $30(2) + $25(3)

= $20 + $60 + $25

= $155

This, the profit = $220 - $155 = $65

However; In manufacturing A units of product A, B unit of product B & C units of product C.

Profit  --> 50A + 80B + 65C

This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40

The current demand is:

100 - A

80 - B

90 - C respectively

So, the total penalty

{(100 - A) + (80 - B) +(90 - C) } + \$40

This should be subtracted from profit.

So, we have to maximize the profit  

Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};

Subject to constraints;

we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity

Then;

2A + B +C \le 300 due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.

Next; demand for A, B, C will not exceed 100, 80, 90 units.

Hence;

A \le 100

B \le 80

C \le 90

 

and A, B, C \ge 0 because they are positive quantities

The objective is:

\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}

A, B, C \to Decision Varaibles;

Constraint are:

A \le 100 \\ \\  B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0

6 0
3 years ago
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Naya [18.7K]

the answer would be 3 because 8 + (-2) is the same as subtraction so you would get 6 from that and dividing it by 2 would make it 3, I hope this helps

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Answer:

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Step-by-step explanation:

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3 years ago
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