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ipn [44]
3 years ago
5

What is the equation of a line that is parallel to the line y=10 and passes through the point (-5,8)?

Mathematics
1 answer:
Alika [10]3 years ago
8 0

Answer:

y=8

Step-by-step explanation:

If the horizontal line is at y=8, it crosses through every x value at y=8, including (-5,8)

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an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor
Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

--------------------------------

We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>

<u />

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • The Z-score measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u> </u>

<u />

In this problem:

  • Mean of 8.8 inches, thus \mu = 8.8.
  • Standard deviation of 2.8 inches, thus \sigma = 2.8.

<u />

The interquartile range(IQR) is the difference between the 75th and the 25th percentile.

<u />

25th percentile:

  • X when Z has a p-value of 0.25, so X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 8.8}{2.8}

X - 8.8 = -0.675(2.8)

X = 6.91

75th percentile:

  • X when Z has a p-value of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 8.8}{2.8}

X - 8.8 = 0.675(2.8)

X = 10.69

The IQR is:

IQR = 10.69 - 6.91 = 3.78

What is the diameter, in inches, of the smallest tree that is an outlier?

  • The diameter is <u>1.5IQR above the 75th percentile</u>, thus:

10.69 + 1.5(3.78) = 16.36

The diameter of the smallest tree that is an outlier is of 16.36 inches.

<u />

A similar problem is given at brainly.com/question/15683591

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