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stealth61 [152]
3 years ago
6

It was 96 kilometers from perry to medford. David raced to medford and idled back. If the round trip took 8 hours, what was his

average speed in kilometers per hours?
Mathematics
2 answers:
dalvyx [7]3 years ago
6 0
Time for round trip = 8 hours

thus, time for trip = 8/2 = 4 hours.

Speed = distance / time

= 96/4 = 24 km/h

Thus, his average speed was 24 km/h
valkas [14]3 years ago
3 0
Average speed = (total distance) / (total time)

Average speed = (192 km) / (8 hours) = 24 km per hour .
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Investigate the difference between compounding annually and simple interest
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Step-by-step explanation:

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A = P (1 + rt)

Compound interest formula

A = P(1 + \frac{r}{n})^{nt}

a.

A = 5000 (1 + 0.025*1)\\A=5000(1.025)\\A=5125

Simple interest is $125

b

. A = 5000 (1 + \frac{0.025}{1})^{1*1}      \\A=5000(1.025)\\A= 5125

Compound interest is $125

c. the result for both a and b are the same

d.

A = 5000 (1 + 0.025*3) \\A=5000(1.075) \\A=5375

the simple interest is $375

e

. A = 5000 (1 + \frac{0.025}{1})^{1*3}] \\A=5000(1.025)^3 \\A=5000(1.077)\\A= 5385

the compound interest is $385

f. the result compared, compound interest is $10 more than simple interest

g.

A = 5000 (1 + 0.02*6) \\A=5000(1.12) \\A=5600

the simple interest is $600

h.

A = 5000 (1 + \frac{0.02}{1})^{1*6}] \\A=5000(1.12)^6 \\A=5000(1.9738) \\A= 9869

the compound interest is $4869

i. the result from g and h, h is over 8 times bigger than g.

j. interest compound annually is not the same as simple interest, only for the case of a and b seeing that it is for 1 year. but for 2years and above there is difference as seen in c to h

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2 years ago
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kipiarov [429]

Answer:

Step-by-step explanation:

We have to make 5 place serial number with first two as alphabets and last three as digits.

The alphabets are bonded to first 6 ( A, B, C, D, E, F) where as digits are 10 (say 1 to 10).

Let the serial number be S1 S2 S3 S4 S5.

For Alphabets

For S1 we have 6 alphabets.

Now for S2 we are left with 5 alphabets since there is no repetition one alphabet will be fix for S1.

So the possible combination for S1 S2= 6x5=30.

For Digits

We did the same as we did for alphabets, for S3 we have 10 possibilities, and for S4 and S5 9 and 8 respectively due to the no repetition condition.

So the possible combinations for S3 S4 S5 = 10x9x8=720

So the total number of serial numbers are 30+720=750.

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