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Ugo [173]
3 years ago
6

− 2/3 (−3 − 9x) A) −2 − 9x B) 2 − 9x C) 2 − 6x D) 2 + 6x

Mathematics
2 answers:
ANEK [815]3 years ago
8 0

Answer:

D 2+6x

Step-by-step explanation:

-2/3(-3-9x)

(-2/3×-3)+(-2/3×-9x)

6/3+18x/3 = 2 + 6x

zysi [14]3 years ago
8 0

Answer:

D) 2 + 6x

Step-by-step explanation:

− 2/3 (−3 − 9x)

Distribute

-2/3 * -3   -2/3 * -9x

2 + 6x

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What is 0.0000007 in standard form
hoa [83]

Answer:

Step-by-step explanation:

Scientific form of 0.0000007 = 7 × 10^{-7}

8 0
3 years ago
Read 2 more answers
Consider the accompanying data on breaking load (kg/25mm width) for various fabrics in both an unabraded condition and an abrade
WITCHER [35]

Answer:

The critical value for a one-tailed test with 7 degrees of freedom and level of significance α=0.01 is tc=2.998.

The test statistic (t=1.729) is below the critical value and falls within the acceptance region, so it is failed to reject the null hypothesis.

At a significance level of 0.01, there is not enough evidence to support the claim that the true difference is significantly bigger than 0.

Step-by-step explanation:

We have a matched-pair t-test for the difference.

We have the null and alternative hypothesis written as:

H_0: \mu_d=0\\\\H_a: \mu_d>0

We have n=8 pairs of data. We calculate the difference as:

d_1=U_1-A_1=36.4-28.5=7.9

Then, with this procedure we get the sample for d:

d=[7.9,\, 35,\, 5.5,\, 4.2,\, 6.7,\, -3.7,\, -0.9,\, 3.3]

The sample mean and standard deviation are:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{8}(7.9+35+5.5+. . .+3.3)\\\\\\M=\dfrac{58}{8}\\\\\\M=7.25\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{7}((7.9-7.25)^2+(35-7.25)^2+(5.5-7.25)^2+. . . +(3.3-7.25)^2)}\\\\\\s=\sqrt{\dfrac{985.08}{7}}\\\\\\s=\sqrt{140.73}=11.86\\\\\\

Now, we can perform the one-tailed hypothesis test.

The significance level is 0.01.

The sample has a size n=8.

The sample mean is M=7.25.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=11.86.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{11.86}{\sqrt{8}}=4.1931

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{7.25-0}{4.1931}=\dfrac{7.25}{4.1931}=1.729

The degrees of freedom for this sample size are:

df=n-1=8-1=7

This test is a right-tailed test, with 7 degrees of freedom and t=1.729, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t>1.729)=0.0637

As the P-value (0.0637) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.01, there is not enough evidence to support the claim that the true difference is significantly bigger than 0.

If we use the critical value approach, the critical value for a one-tailed test with 7 degrees of freedom and level of significance α=0.01 is tc=2.998. The test statistic is below the critical value and falls within the acceptance region, so it is failed to reject the null hypothesis.

8 0
3 years ago
The sum of three consecutive odd integers is 153. Find the three odd integers.
igomit [66]
The answer is 50,51 and 52
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3 years ago
Please help me Asap!! I don't have much time to answer this. Will give brainliest!<br> NO LINKS!!
Advocard [28]

Answer:

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Step-by-step explanation:

<u>Number of those drive to school:</u>

  • 2 + 13 + 25 = 40

<u>Number of those don't drive:</u>

  • 100 - 40 = 60

<u>Probability:</u>

  • P(Drive to school ' ) = 60/100 = 3/5
5 0
2 years ago
Trevor Has a Fair coin and a six-sided number cube with a number 1 through 6 on each side. He flips the coin and rolls a number
mina [271]

Answer:

1/12

Step-by-step explanation:

When you are doing probability with multiple things at once you have to multiply the probabilities of each asked number from each object together to get the probability of them both landing on those numbers

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