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zimovet [89]
3 years ago
9

Help me .............​

Mathematics
1 answer:
Vlad [161]3 years ago
4 0

Answer:#1 = 16

#2 = 4

Step-by-step explanation:

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1/5 of 25 = 25 divided by 5=
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A college professor never finishes his lecture before the end of the hour and always finishes his lectures within 2 min after th
Citrus2011 [14]

Answer:

Value of k is \displaystyle\frac{3}{8}      

Step-by-step explanation:

We are given the following information in the question:

f(x) = kx^2, 0\leq x \leq 2\\~~~~~~~= 0, \text{ otherwise}

where x is the time elapses between the end of the hour and the end of the lecture.

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Since, f(x) is the pdf, then,

\displaystyle\int^\infty_{-\infty} f(x) = 1\\\\\displaystyle\int^2_{0} f(x) = 1\\\\\displaystyle\int^2_{0} kx^2 = 1\\\\k\bigg[\frac{x^3}{3}\bigg]^2_0 = 1\\\\k\times \frac{8}{3} = 1\\\\k = \frac{3}{8}

Hence, value of k is \displaystyle\frac{3}{8}

4 0
3 years ago
andres has 4 bunches of balloons. there are 6 balloons in each bunchs how many balloons does andres have in all
Whitepunk [10]

\large{|\underline{\mathtt{\red{G}\blue{i}\orange{v}\pink{e}\blue{n}\purple{}\green{}\red{↯}\blue{}\orange{}}}}

1 bunch of balloons contain 6 balloons

\large{|\underline{\mathtt{\red{T}\blue{o}\orange{\:}\pink{F}\blue{i}\purple{n}\green{d}\red{↯}\blue{}\orange{}}}}

Number of balloons in 4 bunches = ?

\large\underline{\underline{\maltese{\purple{\pmb{\sf{\: Solution :-}}}}}}

  • <em>To</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>balloons</em><em> </em><em>in</em><em> </em><em>4</em><em> </em><em>bunches</em><em> </em><em>we</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>multiply</em><em> </em><em>the</em><em> </em><em>bumber</em><em> </em><em>of</em><em> </em><em>balloons</em><em> </em><em>in</em><em> </em><em>1</em><em> </em><em>bunch</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>bunches</em><em>.</em>

\tt\multimap \: number \: of \: balloons \: in \: 1 \: bunch \times number \: of \: bunches

\sf \nrightarrow \: 6 \times 4 = 24

➪ <em>T</em><em>h</em><em>u</em><em>s</em><em>,</em><em> </em><em>T</em><em>h</em><em>e</em><em>r</em><em>e</em><em> </em><em>a</em><em>r</em><em>e</em><em> </em><em>2</em><em>4</em><em> </em><em>b</em><em>a</em><em>l</em><em>l</em><em>o</em><em>o</em><em>n</em><em>s</em><em> </em><em>i</em><em>n</em><em> </em><em>4</em><em> </em><em>b</em><em>u</em><em>n</em><em>c</em><em>h</em><em>e</em><em>s</em><em>.</em><em>.</em><em>.</em><em>~</em>

8 0
2 years ago
Read 2 more answers
How do you solve this?<br> 5x-4y+6x<br> if x=8
ololo11 [35]
First plug in the numbers 5 x 8 = 40
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40-4y+48
6 0
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