30pts<br> 8x-7y=23 solve for y

Please help me with this!!

V125BC [204]

Answer:

its B

Step-by-step explanation:

5 0

3 years ago

Which of the following best describes the graph below?

docker41 [41]

<h3>Answer: B.) it is a one-to-one function</h3>

Explanation:

It's a function because it passes the vertical line test. It's also one-to-one because it passes the horizontal line test.

The vertical line test is where we try to draw a single line through more than one point on the blue curve. Such a task isn't possible in this case, and we consider the curve passing the vertical line test. The horizontal line test is nearly identical, but we're dealing with horizontal lines of course.

5 0

3 years ago

12 points and brainliest pls and thank you ! (no unknown links or ill report u and ur whole acc)

lorasvet [3.4K]

Answer:

13

cuz one of those square part = to 90 degrease

so 77 degrease is already shown so minus 90-77

and u get 14

6 0

3 years ago

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Find dy/dx by implicit differentiation for ysin(y) = xcos(x)

tatyana61 [14]

Answer:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

Step-by-step explanation:

So we have:

$y\sin(y)=x\cos(x)$

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

$\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]$

Let's do each side individually.

Left Side:

We have:

$\frac{d}{dx}[y\sin(y)]$

We can use the product rule:

$(uv)'=u'v+uv'$

So, our derivative is:

$=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]$

We must implicitly differentiate for y. This gives us:

$=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]$

For the sin(y), we need to use the chain rule:

$u(v(x))'=u'(v(x))\cdot v'(x)$

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

$=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})$

Simplify:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}$

And we are done for the right.

Right Side:

We have:

$\frac{d}{dx}[x\cos(x)]$

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

$=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]$

Differentiate:

$=\cos(x)-x\sin(x)$

So, our entire equation is:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)$

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

$\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)$

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

And we're done!

5 0

3 years ago

At last, we stopped running. Relief washed over us. Whatever had been chasing us was long gone. We were home and finally safe be

Dmitry_Shevchenko [17]

Answer:

The author is stating his or her feelings.

Step-by-step explanation:

It says "Relief washed over us. Whatever had been chasing us was long gone. We were home and finally safe behind a locked door." She's /he's telling the emotions.

8 0

3 years ago

Read 2 more answers

30pts 8x-7y=23 solve for y