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Anastasy [175]
3 years ago
12

Find the inverse of the function y = x^2 + 12x

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
7 0

Answer:

y=x\\

x=y^{2} + 12y\\

y^{2} + 12y -x = 0\\

Delta = (12^{2}) - 4.1.(-x) = 144 +4X = 36.(4+x)

\sqrt{Delta} = 6 . \sqrt{(4+x)} \\

y' = \frac{-12 + 6.(\sqrt{(4+x)}}{2} = -6 + 3.\sqrt{(4+x)}\\

y" = -6 - 3.\sqrt{(4+x)}\\\\

y' = 3.\sqrt{(4+x)} - 6\\

y''= -3.\sqrt{(4+x)} - 6\\

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Answer:

Chandra's Average Monthly Expenses are;

1) For Both Jan and Feb are $269

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Step-by-step explanation:

From Chandra's matrix all monthly expenses are all same that is,

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February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

March = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

April = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

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June = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

July= $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

August = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

September = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

October = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

November = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

December = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

Therefore Chandra's Average Monthly Expenses are:

1) January & February  = \frac{71 + 1,025 + 75 + 25 + 425 + 120 + 145}{7} = \frac{1886}{7} = 269.4286 to the nearest cent

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2) For the remaining 10 month are = \frac{71 + 1,025 + 75 + 25  + 120 + 145}{6} = \frac{1461}{6}= 243.5 to the nearest cent

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