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3 years ago

Why did the Vietnam vets feel alienated when they came home from war

Mathematics

1 answer:

Marrrta [24]3 years ago

6 0

Answer:

Because they were suffering form PTSD and questioning their identity.

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Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago

A pile of earth removed from an excavation is a cone measuring 6ft high and 30ft across its base. How many trips will it take to

nignag [31]

Answer: 14

Step-by-step explanation:

Given

Excavation cone measures

height $h=6\ ft$

Diameter $d=30\ ft$

Truck can dump $125\ ft^3$ at a time

The volume of a cone is

$V=\dfrac{1}{3}\pi r^2h$

Putting values

$\Rightarrow V=\dfrac{1}{3}\times \pi\times 15^2\times 6\\\Rightarrow V=1413.9\approx 1414\ ft^3$

No of trips(N) required to accumulate this much volume is given by

$\Rightarrow N=\dfrac{1414}{125}=13.3\approx 14$

Therefore, 14 trips are necessary to accumulate a cone of volume $1414\ ft^3$

8 0

3 years ago

What’s the answer for both questions?

Tatiana [17]

Answer:

Step-by-step explanation:

4 0

2 years ago

I need to know the answer for “x” please!

Sergio [31]

Answer:

x r 1.26 cm

Step-by-step explanation:

This can easily be solved by congruence.

Both triangles have the same proportions.

9.8 : 8.8 = (2 + 9.2) : (x + 8.8)

Because these are proportional, we can use and write this as if they were fractions.

9.8 / 8.8 = (2 + 9.2) / (x + 8.8)

multiply crosswise, gives:

9.8 * (x + 8.8) = (2 + 9.2) * 8.8

9.8 * x + 9.8 * 8.8 = (11.2) * 8.8

9.8 * x + 86.24 = 98.56

9.8 * x = 98.56 - 86.24

9.8 * x = 12.32

Divide left and right of the = sign by 9.8 gives,

x = 12.32 / 9.8

x = 1.2(571428)

x = 1.26 cm

8 0

3 years ago

Anthony bikes a 16.2 mile long trail. If he bikes it for 4 times, how far will he have traveled? Draw a bar diagram to help you.

guapka [62]

16.2 * 4 = 64.8 miles

Anthony bikes 64.8 miles

3 0

3 years ago