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3 years ago

Find the average of -25,-70,15,-31,-25,40

Mathematics

1 answer:

denis-greek [22]3 years ago

5 0

$\frac{ - 25 + ( - 70) + 15 + ( - 31) + ( - 25) + 40}{6} = \frac{ - 96}{6} = - 16$

Answer: -16

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kramer

The amount of sugar he will use is 5.22 cups of sugar, and the number of boxes needed to pack the muffins is 13.71 boxes.

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This word problem question can be solved as follows:

Amount of sugar he will use = 1 1/7 * 4 4/7 = 1.142857142857143 * 4.0.571428571428571 = 5.22 cups of sugar

Number of boxes needed to pack the muffins for the meeting = 4 4/7 * 3 = 4.0.571428571428571 * 3 = 13.71 boxes

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1 year ago

Akshay purchased goods costing ₹5,00,000 and sold at 20% profit on cost. Calculate the selling price of goods.

andrey2020 [161]

Answer:

the selling price of the goods is ₹6,00,000

Step-by-step explanation:

The computation of the selling price of the goods are shown below:

As we know that

Selling price = Cost price + profit

= 5,00,000 + 5,00,000 × 0.20

= 5,00,000 + 1,00,000

= ₹6,00,000

Hence, the selling price of the goods is ₹6,00,000

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2 years ago

In a Gallup poll, 1025 randomly selected adults were surveyed and 29% of them said that they used the Internet for shopping at l

svetoff [14.1K]

Answer: (0.25,0.33)

Step-by-step explanation:

A 99% confidence interval for population proportion is given by:-

$\hat{p}\pm 2.576\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$ , where $\hat{p}$ = sample proportion, $n$ = sample size.

Given: $n=1025, \hat{p}=0.29$

A 99% confidence interval estimate of the proportion of adults who use the Internet for shopping:

$0.29\pm 2.576\sqrt{\dfrac{0.29(1-0.29)}{1025}}\\\\=0.29\pm 2.576\sqrt{0.00020087804878}\\\\=0.29\pm2.576(0.01417)\\\\=0.29\pm0.03650192\\\\=(0.29-0.03650192,\ 0.29+0.03650192)\\\\=(0.25349808,\ 0.32650192)$

$\approx(0.25,\ 0.33)$

Thus, a 99% confidence interval estimate of the proportion of adults who use the Internet for shopping = (0.25,0.33)

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3 years ago

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vovangra [49]

Answer:

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2 years ago

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2 years ago