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BlackZzzverrR [31]
2 years ago
10

If andre collects $9.80, how many cups did he sell?

Mathematics
1 answer:
barxatty [35]2 years ago
5 0

Answer:

we need more information

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simplify the following polynomial expression. <img src="https://tex.z-dn.net/?f=%285x%5E%7B3%7D%20%2B4x%5E%7B2%7D%20%2B6x-3%29%2
FrozenT [24]
Here is the answer hope it helps

7 0
3 years ago
Write the expression that represents the volume of the prism in cubic units
xz_007 [3.2K]
Volume = w * 2w * 3w = 6w^3  cubic units
6 0
3 years ago
If your scale factor is negative, the image will be rotated 180 degrees?
Tamiku [17]

Answer:

yes it's rotated 180 degree angle

5 0
3 years ago
Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt
tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

f(x)= \sqrt{\dfrac{x+1}{x-1}}

g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

\dfrac{x+1}{x-1}>0

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

x+1\leq 0\Rightarrow x\leq -1

x-1\leq 0\Rightarrow x\leq 1

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0
3 years ago
I need help pls and thank you
kobusy [5.1K]

Answer:

unbounded region

A feasible region that cannot be enclosed in a closed figure is known as an unbounded region. A feasible region is a set of all possible points of an optimization problem that satisfy the problem's constraints; feasible sets may be bounded or unbounded.

Step-by-step explanation:

4 0
3 years ago
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