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Alisiya [41]
3 years ago
14

Which correctly describes a cross section of the cube below? Check all that apply.

Mathematics
1 answer:
yarga [219]3 years ago
5 0

<u>A cross section parallel to the base is a square measuring 4 cm by 4 cm </u>

<u>Step-by-step explanation:</u>

Here we have to select the correct  statement regarding a cross section of the cube :

<u>A cross section parallel to the base is a square measuring 4 cm by 4 cm :</u>

Since , every side of a cube is same  . Any cross section of a cube must be parallel to a square base . Hence, correct statement .

<u>A cross section parallel to the base is a rectangle measuring 4 cm by greater than 4 cm :</u>

Since , every side of a cube is same  . Any cross section of a cube must be parallel to a square base . Here, base is rectangle . We don't have a rectangle base in cube . Not correct statement.

<u>A cross section perpendicular to the base through the midpoints of opposite sides is a rectangle measuring 2 cm by 4 cm:</u>

Since , every side of a cube is same  . Any cross section of a cube must be parallel to a square base . Here, base should be square not rectangle . So ,  Not correct statement.

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3. The standard equation of a circle (not centered at the origin) with radius r can be derived from its locus definition: The se
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Answer:

The  equation for  circle of radius r centered at the point C: (h,k) is:

(x-h)^2+(y-k)^2=r^2

Step-by-step explanation:

To derive this equation, we need the formula for the distance between two points in the plane. If the point is given by its cartesian coordinates, we can use the Pythagorean theorem to find what the distance between the points is.

Lets say we have two points, one given by cartesian coordinates P:(x,y) and the other given by cartesian coordiantes C:(h,k)

(see diagram)

We can see that

\Delta x = x-h\\\Delta y = y-k

and by the pythagorean theorem we have:

\Delta s ^2 = \Delta x^2 + \Delta y^2

Where \Delta s is the distance between the points

Now, combining the last three equations we find:

\Delta s ^2 = (x-h)^2 + (y-k)^2

We know that the definition of a circle is the locus of points that are at a distance r from a point called the center of the circle. if we take C:(h,k) as the center of the circle, and \Delta s  =r , the last equation becomes:

r^2 = (x-h)^2 + (y-k)^2

And that is the result we wanted.

6 0
3 years ago
Jam World Amusement Park sells special multi-day passes for guests who want to visit the park for more than one day. Their most
TiliK225 [7]

Answer:

17 dollars more

Step-by-step explanation:

3 0
2 years ago
Need mad help bro, this is so confusing
statuscvo [17]
im doing the same thing but add some numbers sorry bro im failing
3 0
3 years ago
I'll. ark brainlyest and give a lot of points for answering this right ​
valina [46]

Answer:

\displaystyle T'(  2,4)

\displaystyle U'( 1,1)

\displaystyle S' ( 3,2)

Step-by-step explanation:

we current vertices of the given triangle

  • \displaystyle T( - 2,4)
  • \displaystyle U( - 1,1)
  • \displaystyle S ( - 3,2)

remember that,

\rm\displaystyle(x,y) \xrightarrow{ \rm reflection \:  over \: y - axis}( -  x,y)

so we obtain:

\rm\displaystyle \: T( - 2,4) \xrightarrow{ \rm reflection \:  over \: y - axis}T'(  2,4)

\rm\displaystyle \: U( - 1,1) \xrightarrow{ \rm reflection \:  over \: y - axis}U' ( 1,1)

\rm\displaystyle S( - 3,2) \xrightarrow{ \rm reflection \:  over \: y - axis}S'( 3,2)

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3 years ago
Corey uses exactly 50 yards of wire fence to create a triangular pen for his dog in his
Oliga [24]
16. 50-18=32
32/2=16
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4 years ago
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