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weqwewe [10]
3 years ago
10

What is the multiplicative rate of change of the function shown on the graph? Express your answer in decimal form. Round to the

nearest tenth.

Mathematics
2 answers:
allsm [11]3 years ago
6 0
In linear models there is a constant additve rate of change. For example, in the equation y = mx + b, m is the constanta additivie rate of change.


In exponential models there is a constant multiplicative rate of change.


The function of the graph seems of the exponential type, so we can expect a constant multiplicative exponential rate.


We can test that using several pair of points.


The multiplicative rate of change is calcualted in this way:

 [f(a) / f(b) ] / (a - b)

Use the points given in the graph: (2, 12.5) , (1, 5) , (0, 2) , (-1, 0.8)

[12.5 / 5] / (2 - 1) = 2.5


[5 / 2] / (1 - 0) = 2.5


[2 / 0.8] / (0 - (-1) ) = 2.5


Then, do doubt, the answer is 2.5





Goryan [66]3 years ago
4 0

Answer:

Multiplicative rate of change is 2.5

Step-by-step explanation:

Let the given exponential function is in the form of y=a(r)^{x}

where a = initial value

x = duration or time

r = rate of change

For point (0, 2)

2=a(r)^{0}

a = 2

Now the exponential equation becomes y=2(r)^{x}

For the point (1, 5)

5=2(r)^{1}

r=\frac{5}{2}

r = 2.5

Therefore, multiplicative rate of change is 2.5

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Step-by-step explanation:

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In the data set below, what is the median
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What is the equation of the following graph.
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Read 2 more answers
USE THE ATTACHED IMAGE BELOW TO HELP DO MY HOMEWORK PLEASE<br> !!!!
BartSMP [9]

Part A

Sue

A = P*(1+r/n)^(n*t) is the compound interest formula

A = 2300*(1+0.024/1)^(1*3)

A = 2469.6061952

A = 2469.61

A - P = 2469.61-2300 = 169.61

<h3>Sue gets 169.61 pounds in interest</h3>

-----------

Bill

A = P*(1+r/n)^(n*t)

A = 1800*(1+0.034/1)^(1*3)

A = 1989.9131472

A = 1989.91

A-P = 1989.91-1800 = 189.91

<h3>Bill earns 189.91 pounds in interest</h3>

Bill has earned more in interest.

=====================================================

Part B

By year 2, Bill has 1924.48 pounds in his account based on the work shown below

A = P*(1+r/n)^(n*t)

A = 1800*(1+0.034/1)^(1*2)

A = 1924.4808

A = 1924.48

This amount is the new deposit, so to speak, when we change the interest rate. Now r = 0.034 changes to r = 0.04. We only go for one year so t = 1

A = P*(1+r/n)^(n*t)

A = 1924.48*(1+0.04/1)^(1*1)

A = 2001.4592

A = 2001.46

Bill has 2001.46 pounds in his account after 3 years if the interest rate for the 1234 account changes to 4% in the third year.

Now subtract off the original amount Bill deposited to get

2001.46-1800 = 201.46

For this scenario, Bill earns 201.46 pounds in interest.

Therefore, Bill has earned the most interest for both cases of the interest rate staying at 3.4% or changing to 4% for that third year.

<h3>Answer: Bill</h3>
8 0
3 years ago
Help ASAP due in 6 mins
vova2212 [387]

Answer:

the answer is confusing but you have to put it in as an equation and get and answer then you simplify that answer into a number sequence by rounding and estimating

Step-by-step explanation:

7 0
3 years ago
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