All categories

2 years ago

PLEASE HELP WILL MARK BRAINLIEST PLZ PLZ PLEASE!!

Mathematics

2 answers:

ValentinkaMS [17]2 years ago

7 0

Answer:

1) C

2) B

3) A,B, and C

4) C

5) B

6) C

Step-by-step explanation:

OLEGan [10]2 years ago

4 0

Answer:

1. C

2. B

3. A, B, C

4. C

5. B

6. C

Step-by-step explanation:

1. You can remember the name by just looking at their positions- they alternate and they're on the exterior

2. They are supplementary meaning they add to 180°, set the angle measures up to 180 and solve for x!

76 + 2x = 180

2x = 104

x = 52

3. Equilateral trinagles have these qualities

4. Those hashes on the sides of the triangles signify those sides are the same length- that means the angles opposite of those sides share the same angle measure. If you know two angles are 35, and the last angle is 2x, you can set up an equation:

35 + 35+ 2x = 180

70 + 2x = 180

2x = 110

x = 55

5. That square means a right angle which equals 90°, like question 4, you set up an equation!

90 + 5x + 5x = 180

90 + 10x = 180

10x = 90

x = 9

6. Set up a proportion.

12 : 30 // 12(x) = 30, x = 2.5

8 : y // 8(2.5) = y, y = 20

You might be interested in

The width of a rectangular sandbox is two less than twice the length. The perimeter of the sandbox is 26 feet. Identify the leng

DedPeter [7]

$l = 5 \\ w = 8$

5 + 5 + 8 + 8 = 26 and since 5 x 2 - 2 = 8 it matches with the problem

4 0

3 years ago

Read 2 more answers

What is the equation for the line shown on this graph?

ratelena [41]

Y=-7
Since it’s a straight line, there is no slope. So this is a zero slope line.

6 0

3 years ago

Integration by Parts Evaluate e-2x cos(2x) dx.

kifflom [539]

Let

$I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]texIntegrate by parts:[tex]\displaystyle \int u \, dv = uv - \int v \, du$

with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \cos(2x) \, dx \implies v = \dfrac12 \sin(2x)$

Then

$\displaystyle I = \frac12 e^{-2x} \sin(2x) + \int e^{-2x} \sin(2x) \, dx + C$

Integrate by parts again, this time with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \sin(2x) \, dx \implies v = -\dfrac12 \cos(2x)$

so that

$\displaystyle I = \frac12 e^{-2x} \sin(2x) - \frac12 e^{-2x} \cos(2x) - \int e^{-2x} \cos(2x) \, dx + C\\\\ \implies I = \frac{\sin(2x)-\cos(2x)}{2e^{2x}} - I + C \\\\ \implies 2I = \frac{\sin(2x) - \cos(2x)}{2e^{2x}} + C \\\\ \implies I = \boxed{\frac{\sin(2x) - \cos(2x)}{4e^{2x}} + C}$

6 0

1 year ago

What is 5 1/4 divided by 7?

NARA [144]

ANSWER: I think it’s 3/4

4 0

3 years ago

Read 2 more answers

Any one good with proportion

olasank [31]

Answer:

4. No

5. No

6. No

7. No

8. No

9a. 2 : 3 = 8 : 12 Extremes: 2, 12. Means: 3, 8

9b. 90 : 36 = 135 : 54 Extremes: 90, 54. Means: 36, 135

Step-by-step explanation:

4. 12 : 25 and 6 : 13 are NOT equal. NO.

5. 64 : 120 = 8 : 15 and 60 : 100 = 3 : 5. NOT equal. NO

6. 37 : 115 and 296 : 966 = 148 : 483. NOT equal. NO

7. 300 : 200 = 3 : 2 and 6 : 5 are NOT equal. NO.

8. 8 : 10 = 4 : 5 and 11 : 14 are NOT equal. NO.

9a. 2 : 3 = 8 : 12 Extremes: 2, 12. Means: 3, 8

9b. 90 : 36 = 135 : 54 Extremes: 90, 54. Means: 36, 1135

6 0

3 years ago