D. A struggle for existence is apparent.
If a struggle for existence is apparent, natural selection occurs because all of the weak/unfit/unadapted ones die.
Your answer is A) Recombinant DNA. I just took this quiz. Thanks
Answer:
P. aeruginosa
Explanation:
<em>P. aeruginosa</em> is a gram-negative bacteria that belongs to the family Pseudomonadaceae.
From the given question the following points lead us to conclude that the colony that will be growing would be of P. aeruginosa :
1. Flat spreading colonies with a metallic sheen on SBA - <em>P. aeruginosa</em> is known to produce smooth colonies with flat edges.
2. Fluorescent green color in the media with clear colonies on cetrimide agar - <em>P. aeruginosa</em> is known to produce pyoverdin which is a fluorescent pigment under low iron conditions.
3. Medium clear colonies that have a "fruity or grape-like odor" on MacConkey Agar - <em>P. aeruginosa</em> has a sweet fruity odor which is its characteristic odor because of the production of trimethylamine.
Thus, from all these characteristics one can conclude that the organism in the culture is <em>P. aeruginosa. </em>
Answer:
The correct answer is synapse, electrical signals, neurotransmitters.
Explanation:
Neuron communicates with other neurons via action potentials and chemical neurotransmitters through the synapse.
Two neurons form a junction that is termed as a synapse, there an action potential that results in neuron A to release a neurotransmitter (chemical).
Synapses are thought of as the site of converting an electrical signal into a neurotransmitter release which is a chemical signal.
Thus, the correct answer is synapse, electrical signals, neurotransmitters.
(1) All the genotypes are as follows: AABB, AaBB, AABb, AaBb, aaBB, aaBb, AAbb, Aabb, aabb.
(2) Assuming that Aa is dominant and Bb is recessive, there will be 9 phenotypes with both A and B allele dominant (i.e. AaBb, AABb); there will be 3 phenotypes with just the A allele dominant (i.e. Aabb, AAbb); there will be 3 phenotypes with just the B allele dominant (i.e. aaBb, aaBB); and there will be 1 phenotype with both alleles recessive (i.e. aabb). The phenotypic ratio in this case is 9:3:3:1.
(3) The probability of producing an offspring with the aabb genotype is 1/16 or 6%.