Both a man and a woman are heterozygous for freckles. Freckles ( F) are dominant over no freckles ( f). What is the chance that
their child will have freckles?
1 answer:
Answer:
75% chance or 3/4
Explanation:
If both parents are heterozygous and freckles is a dominant trait (F) then we can denote having no freckles as (f)
Using a punnett square, this will produce the following genotypes of the children:
FF, Ff, Ff and ff.
Therefore, there's a 3 out 4 chance or 75% of the children also inheriting freckles.
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