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3 years ago

Marcus is buying taco shells for a party. There will be 13 adults and 17 children

Mathematics

1 answer:

vladimir1956 [14]3 years ago

5 0

Answer:

Tacos for adults: 13*3

Tacos for children: 17*1

Total: 39+17

=56

And in each package there will be 8 tacos

So, 56/8 = 7 = No. of tacos needed.

So the corrrect answer is<u> A 7, because (13 x 3 + 17) + 8 = 7</u>

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Calculate 11010-1101 in base 2

stiv31 [10]

Answer:

1101 base 2

Step-by-step explanation:

you first take the larger number up the the lower number down

11010 -1101
when dividing if it's zero you borrow one from the number on the left hand side
since it's in base 2 the number you borrow would be 2 then u subtract
I hoped it helped u

6 0

2 years ago

−2x=x^2 −6 from khan academy helppppppp please

masya89 [10]

This is in its simplest form.
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5 0

2 years ago

Decide whether a triangle with side lengths of sqr5, 5, and 5.5 is right, acute, or obtuse.

LUCKY_DIMON [66]

It is acute isosceles triangle

4 0

2 years ago

20 POINTS PLS HELP ASP

3241004551 [841]

Answer:

x=65°

Step-by-step explanation:

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x+25=90

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8 0

2 years ago

Sandra knows the Pythagorean identity sin 2 ⁡ θ + cos 2 ⁡ θ = 1 . If she is told that 0 ≤ θ ≤ π 2 and cos ⁡ θ = 5 12, what will

slavikrds [6]

Answer:

$\text{tan}(\theta)=\frac{\sqrt{119}}{5}$

Step-by-step explanation:

We have been given that Sandra knows the Pythagorean identity $\text{sin}^2(\theta)+\text{cos}^2(\theta)=1$ . She is told that $0\leq \theta\leq \frac{\pi}{2}$ and $\text{cos}(\theta)=\frac{5}{12}$ .

First of all, we will find value of sine theta using the given identity.

$\text{sin}^2(\theta)+\text{cos}^2(\theta)=1$

$\text{sin}^2(\theta)+(\frac{5}{12})^2=1$

$\text{sin}^2(\theta)+\frac{25}{144}=1$

$\text{sin}^2(\theta)+\frac{25}{144}-\frac{25}{144}=1-\frac{25}{144}$

$\text{sin}^2(\theta)=\frac{144-25}{144}$

$\text{sin}^2(\theta)=\frac{119}{144}$

$\text{sin}(\theta)=\sqrt{\frac{119}{144}}$

$\text{sin}(\theta)=\frac{\sqrt{119}}{12}$

$\text{tan}(\theta)=\frac{\text{sin}(\theta)}{\text{cos}(\theta)}$

$\text{tan}(\theta)=\frac{\frac{\sqrt{119}}{12}}{\frac{5}{12}}$

$\text{tan}(\theta)=\frac{\sqrt{119}*12}{5*12}=\frac{\sqrt{119}}{5}$

Therefore, $\text{tan}(\theta)=\frac{\sqrt{119}}{5}$ .

5 0

3 years ago