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dolphi86 [110]
3 years ago
8

There are 365 days in a common year how many comman days in 3 common year

Mathematics
2 answers:
alisha [4.7K]3 years ago
8 0
Dice there are 365 days is a year, all you would need to do is multiply 365 by 3

365x3
kari74 [83]3 years ago
4 0
I guess you just have to multiply 365 x 3. Since there is 365 days in one year, just add it two more times to see how many days in all. So the answer should be 1,095. 
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helen has 30 tickets.Gina has 20 more tickets thank helen.what percent of tickets must Gina give helen so that both of them can
iren [92.7K]
Helen = 30 T (T = tickets)
Gina = 30 + 20 = 50 T

20% of 50 = 10

30 + 10 = 404
50 - 10 = 40

Gina must give 20% of her tickets for them to have equal amount of tickets.

Hope this helps!!
4 0
3 years ago
Regular Hourly Rate = $6.50 Total Work Hours = 48 Overtime Rate = Time
Vikki [24]

Answer:

2212$

Step-by-step explanation:

6 0
3 years ago
Y=2(x+4)^2-21<br><br> Convert the equation from vertex form to standard
PSYCHO15rus [73]

Answer:

y = 2x² + 16x + 11

I hope im right... If not reaaally sorry!!

7 0
3 years ago
100 POINTS, WILL MARK BRAINLIEST! If h(x) = f[f(x)] use the table of values for f and f ′ to find the value of h ′(1).
victus00 [196]

Answer:

The value of h^\prime(1)=5

Step-by-step explanation:

Given that  h(x)=f(f(x))

now to find h(x)=f(f(x)) from the given functions f(x) and f'x

let h(x)=f(f(x))

Then put x=1 in above function we get

h(1)=f(f(1))

=f(3) (from the table f(1)=3 and f(3)=6)

Therefore h(1)=6

Now to find h'(1)

Let

h^{\prime}(x)=f^{\prime}(f^\prime(x)) (since  h(x)=f(f(x)) )

put x=1 in above function we get

h^{\prime}(1)=f^{\prime}(f^\prime(1))

=f^{\prime}(2)    (From the table f^\prime(1)=2 and f^\prime(2)=5)

h^{\prime}(1)=5

Therefore h^{\prime}(1)=5

4 0
3 years ago
Read 2 more answers
Butyric acid ( c3h7cooh) is a weak acid . what is the ph of a 0.0250 m solution of this acid. ka = 1.5 x 10-5 (2 decimal places)
Wewaii [24]

The pH of the weak acid is 3.21

Butyric acid is known as a weak acid, we need the concentration of [H+] formula of weak acid which is given by this equation :

[H^{+}]=\sqrt{Ka . Ma}

where [H+] is the concentration of ion H+, Ka is the weak acid ionization constant, and Ma is the acid concentration.

Since we know the concentration of H+, the pH can be calculated by using

pH = -log[H+]

From question above, we know that :

Ma = 0.0250M

Ka = 1.5 x 10¯⁵

By using the equation, we can determine the concentration of [H+]

[H+] = √(Ka . Ma)

[H+] = √(1.5 x 10¯⁵ . 0.0250)

[H+] = 6.12 x 10¯⁴ M

Substituting the value of [H+] to get the pH

pH = -log[H+]

pH = -log(6.12 x 10¯⁴)

pH = 3.21

Hence, the pH of the weak acid c3h7cooh is 3.21

Find more on pH at: brainly.com/question/14466719

#SPJ4

8 0
1 year ago
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