1. Rewrite the system:
x+12y=68 (i)
x=8y-12 (ii)
2. Let's substitute the equation (ii) into the equation (i):
x+12y=68
(8y-12)+12y=68
3. Then, you have:
8y-12+12y=68
4. When you clear "y", you have:
20y-12=68
20y=68+12
20y=80
y=80/20
y=4
5. You already have the value of "y". Now, you must substitute this value into the equation (ii):
x=8y-12
x=8(4)-12
x=32-12
x=20
6. Therefore, the result is:
x=20
y=4
Answer:
229.7
Step-by-step explanation:
8 * 1/2 * 5.8 * 7 * sqrt(2.)
3 feet= 1 yard
16*3= 48 feet.
47.52/48= 0.99
It will cost Brian $0.99 per foot.
Find the unit rate.
49.50/50= 0.99
No, it wouldn't. It would be the <em>same price
0.99=0.99 It doesn't matter which one Brian chose. </em>
I hope this helps!
~kaikers
Pretty sure it would be 5x u less theres more to the problem
Answer:
x = 21
Step-by-step explanation:
To see for what value of x is the equation true, we have to solve x.
![\displaystyle \frac{2}{3} x - 3 = 11\\\\Adding \ 3 \ to \ both \ sides\\\\\frac{2x}{3} = 11 + 3\\\\\frac{2x}{3} = 14\\\\Multiply \ 3 \ to \ both \ sides\\\\2x = 14 \times 3\\\\2x = 42 \\\\Divide\ both\ sides\ by\ 2\\\\x = 42/2\\\\x = 21\\\\For \ x = 21\ the \ given \ equation \ is \ true.\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B2%7D%7B3%7D%20x%20-%203%20%3D%2011%5C%5C%5C%5CAdding%20%5C%203%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C%5Cfrac%7B2x%7D%7B3%7D%20%3D%2011%20%2B%203%5C%5C%5C%5C%5Cfrac%7B2x%7D%7B3%7D%20%3D%2014%5C%5C%5C%5CMultiply%20%5C%203%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C2x%20%3D%2014%20%5Ctimes%203%5C%5C%5C%5C2x%20%3D%2042%20%5C%5C%5C%5CDivide%5C%20both%5C%20sides%5C%20by%5C%202%5C%5C%5C%5Cx%20%3D%2042%2F2%5C%5C%5C%5Cx%20%3D%2021%5C%5C%5C%5CFor%20%5C%20x%20%3D%2021%5C%20the%20%5C%20given%20%5C%20equation%20%5C%20is%20%5C%20true.%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3><h3>Peace!</h3>
