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3 years ago

15

Please help due in 1 hour

1 answer:

kaheart [24]3 years ago

4 0

Answer:

<h2>∠CBH = 92°</h2><h2 />

Step-by-step explanation:

see image below

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What is the equation of the line that passes through (0, 3) and (7, 0)?

r-ruslan [8.4K]

The answer should be (C):y=(-3/7)x+3 because:

if you use the slope formula: (Y2-Y1)/(X2-X1) it would look like this:

(0-3)/(7-0) and the slope of the line would be -3/7

then using the slope you just found, plug it into the y=mx+b equation along with one set of coordinates to find b (the y-intercept):

y=mx+b
0=(-3/7)(7)+b
b=3

SO, overall if you put the slope (m) and the y-intercept (b) that you found together, you get the line formula of y=(-3/7)+3

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3 years ago

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Step-by-step explanation:

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Given f(x) and g(x) = f(k:x), use the graph to determine the value of k.

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Please help i need to answer this within 2 hours

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Element X is a radioactive isotope such that its mass decreases by 26% every day. If an experiment starts out with 810 grams of

ioda

Answer:

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the amount of a substance is given by:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Hourly rate of change:

Decreases 26% by day. A day has 24 hours. This means that $A(24) = (1-0.26)A(0) = 0.74A(0)$ ; We use this to find r.

$A(t) = A(0)(1-r)^t$

$0.74A(0) = A(0)(1-r)^{24}$

$(1-r)^{24} = 0.74$

$\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}$

$1 - r = (0.74)^{\frac{1}{24}}$

$1 - r = 0.9875$

$r = 1 - 0.9875 = 0.0125$

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

Starts out with 810 grams of Element X

This means that $A(0) = 810$

Element X is a radioactive isotope such that its mass decreases by 26% every day.

This means that we use, for this equation, r = 0.26.

The equation is:

$A(t) = A(0)(1-r)^t$

$A(t) = 810(1 - 0.26)^t$

$A(t) = 810(0.74)^t$

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

5 0

3 years ago