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OLga [1]
2 years ago
7

Pattern A follows the rule "add 3" and Pattern B follows the rule "add 4." Pattern A 1 4 7 10 13 Pattern B 5 9 13 17 21 Which or

dered pairs are formed from combining a term in Pattern A with its corresponding term in Pattern B? Select all correct answers. (4, 13) (1, 4) (1, 5) (13, 17) (10, 17) (7, 13)
Mathematics
1 answer:
IceJOKER [234]2 years ago
6 0

Answer:

(1,5) (7,13) (10,17) (7,13)

Step-by-step explanation:

1 4  7  10  13

5 9 13 17 21

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I need help, please. I don’t understand
lina2011 [118]

Answer:

60%

Step-by-step explanation:

So, this question is saying the bowls can be between a diameter of 6.95 and 7.05

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Read 2 more answers
The length of a rectangle is 7 more than the width. The area is 744 sqaure yards, find the length and width of the rectangle​
AVprozaik [17]

Answer:

  • Length of rectangle is 31 yards and Width is 24 yards.

Given:

  • The length of a rectangle is 7 more than the width.
  • The area is 744 sqaure yards

Solution:

Let's assume Width of rectangle be x and Length of rectangle be x + 7 respectively.

Using formula

\\  \:  \:  \:  \:  \pink{ \dashrightarrow \:  \:  \:  \:  \sf { \underbrace{Area_{(Rectangle)} =  Length × Width  }}} \\  \\

On Substituting the required values, we get;

\\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf (x)(x + 7) = 744 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf  {x}^{2}  + 7x = 744 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf  {x}^{2}  + 7x - 744 = 0 \\ \\ \\  \: \: \: \:  \dashrightarrow \: \: \: \: \sf  {x}^{2}  + 31x - 24x - 744 = 0 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf x(x + 31) - 24 (x + 31) = 0 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf (x + 31)(x - 24) = 0 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf x = 24 \:  or \:   - 31 \\ \\

As we know that width of the rectangle can't be negative. So x = 24

<u>Hence</u>,

  • Width of rectangle = x = 24 yards
  • Length of the rectangle = x + 7 = 31 yards

\thereforeLength of rectangle is 31 yards<u> </u>and Width is 24 yards.

8 0
2 years ago
 what is perpendicular to y= 3x -9 and passes through the point (3,1)
GREYUIT [131]
(3,1) , \ \ y= 3x -9 \\ \\ The \ slope \ is :m _{1} =3 \\ \\ If \ m_{1} \ and \ m _{2} \ are \ the \ gradients \ of \ two \ perpendicular \\ \\ lines \ we \ have \ m _{1} \cdot m _{2} = -1 \\ \\3\cdot m_{2}=-1 \ \ /:3\\ \\ m_{2}=-\frac{1}{3}

\Now \ your \ equation \ of \ line \ passing \ through \ (3,1) would \ be: \\ \\ y=m_{2}x+b \\ \\1=-\frac{1}{ 3} \cdot3 + b

1=-1+b\\ \\ b=1+1\\ \\b=2 \\ \\ y =- \frac{1}{3}x+2


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