1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
suter [353]
4 years ago
14

Which test point holds true for 3/2y - 2x>1?

Mathematics
2 answers:
Leya [2.2K]4 years ago
8 0

Answer with explanation:

The given Inequality is :

  \frac{3 y}{2} -2 x>1\\\\ \frac{x}{\frac{-1}{2}}+\frac{y}{\frac{2}{3}}>1

Writing the inequality in slope intercept form,of line and then drawing the line

   \frac{x}{\frac{-1}{2}}+\frac{y}{\frac{2}{3}}=1

or the equation of line is , 3 y-4 x=2

and the inequality becomes, 3 y -4 x >2

Checking which points lie on the solution region

Point, (0,0) does not satisfies the inequality.So,color the area on the left of line,also the points on the line will not be included as a solution,as this is an open set.

⇒⇒None of the points lie in the solution region.

cricket20 [7]4 years ago
6 0
For the answer to the question above asking Which test point holds true for 3/2y - 2x>1?
There exists a question that instead of >, the symbol used is ≥. Substitute the value of abscissas and ordinates of the points to x and y, respectively.
The answer to the question above is the first one among the given choices which is <span>A. (1/4, 1)</span>
You might be interested in
Find a ⋅ b. a = &lt;5, 2&gt;, b = &lt;4, 5&gt;
cestrela7 [59]

Answer:

  30

Step-by-step explanation:

For a = <xa, ya> and b = <xb, yb>, the dot product is the sum of products ...

  a·b = (xa)(xb) + (ya)(yb)

Substituting the given information, you have ...

  a·b = 5·4 + 2·5 = 20 + 10

  a·b = 30

_____

Some graphing calculators can do such math. There are also dot product calculators available on the Internet. If you have quite a few of these to calculate, you can put the appropriate formula into a spreadsheet.

6 0
3 years ago
Evaluate k^2-4k+3, when k= -2 <br> PLEASER ANSWER ASAP!!!
velikii [3]

Answer:

7

I hope this helps!

7 0
3 years ago
Please help! Due soon
sesenic [268]

Answer:

its 2/6

Step-by-step explanation:

7 0
3 years ago
(1 point) The systolic blood pressure (given in millimeters) of males has an approximately normal distribution with a mean of 12
garik1379 [7]

Answer:

a) Z = -2.7

b) Z = 2.3

c) Kyle's systolic blood pressure is 1.75 standard deviations above the average systolic blood pressure for men.

d) X = 144.5

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 127, \sigma = 10

(a) 100 millimeters z-score =

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 127}{10}

Z = -2.7

(b) 150 millimeters z-score =

Z = \frac{X - \mu}{\sigma}

Z = \frac{150 - 127}{10}

Z = 2.3

(c) Kyle's doctor told him that the z-score for his systolic blood pressure is 1.75. Which of the following is the best interpretation of his score?

1.75 standard deviations above the mean systolic blood pressure of males.

The problem does not talk about age.

So the answer is:

Kyle's systolic blood pressure is 1.75 standard deviations above the average systolic blood pressure for men.

d) Calculate Kyle's blood pressure

This is X when Z = 1.75. So

Z = \frac{X - \mu}{\sigma}

1.75 = \frac{X - 127}{10}

X - 127 = 1.75*10

X = 144.5

7 0
4 years ago
The students in Mr. McIntyre’s class and the students in Mrs. Ramos’s class were asked how many pets they each have. The dot plo
Mazyrski [523]

The correct statement compares the means of the data in the dot plots is option C; the mode is greater for Mrs. Ramos’s class.

<h3>What are the median and mode of the data?</h3>

Median represents the middle value of the given data when arranged in a particular order.

Mode is that number that appears most frequently in the given set of data.

Given;

The Number of pets in Mr. McIntyre’s class ;

0,0,0,0,0,1, 1, 1, 1, 1, 4, 4, 4, 4, 1,

Median = 1

Mode = 0 and 1

The Number of pets in Mrs. Ramos’s Class;

0, 1, 1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 3, 3, 3

Median = 3

Mode = 4 and 5

Hence, C; The mode is greater for Mrs. Ramos’s class.

The remaining part of the question is

"Which statement correctly compares the measures of center of the data in the dot plots?

The median is greater for Mr. McIntyre’s class.

The median is the same for both classes.

The mode is greater for Mrs. Ramos’s class.

The mode is the same for both classes."

To learn more about median, please check: brainly.com/question/20434777

#SPJ1

6 0
2 years ago
Other questions:
  • HELP ASAP PLZ &amp;THANK YOU :)
    7·1 answer
  • Si f(x) = 1/2x^2-(1/4x+3),¿cuál es el valor de f(8)?<br> (3) 27<br> (2) 17<br> (4) 33<br> (1) 11
    11·1 answer
  • A student earns $11.75 per hour of gardening. if the student worked 21 hours a month then how much did they earn?
    13·2 answers
  • Help me pleaseeeeeee
    11·1 answer
  • ⚠️ANSWER NEEDED SUPER FAST ⚠️ BRAINLIEST TO RIGHT AND QUICK ANSWER
    12·2 answers
  • EASY POINTS!?!?!?!?!?!
    10·1 answer
  • There are 30 students in the class. Eleven have blue eyes.
    7·1 answer
  • Max wants to start a farm to grow mussels. He needs to determine the best environment for growing them. He is going to try two d
    11·1 answer
  • THIS IS A EMERGENCY IM FAILING so BADDD i fell off in 9th grade now im getting 50%
    9·1 answer
  • Can somebody please help me?<br> Answer ASAP
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!