Answer:
B = 5.59x10⁹ T
Explanation:
The magnetic force (F), on a the alpha particle with charge (q) that is moving at velocity (v) as the cross product of the velocity and magnetic field (B) is:
<u>We have:</u>
F = 1.4x10⁻³ N
v = 2.6x10⁶ m/s
θ = 37.0°
q = 2*p = 2*1.6x10⁻¹⁹ C
Hence, the strength of the magnetic field is:
Therefore, the strength of the magnetic field is 5.59x10⁹ T.
I hope it helps you!
Answer:
1.02 seconds
Explanation:
Initial velocity = u = 5 m/s
t = Time taken
s = Displacement travelled = 0
a = Acceleration due to gravity = -9.81 m/s² (negative sign due to direction)
Equation of motion
So, time taken to return to its initial position is 1.02 seconds
Answer:
v0 = 24.42 m/s (Approx)
Explanation:
Given:
Increase in frequency = 7.1% =
Computation:
Assume n = 100%
n1 = [(v+v0)/(v+v1)]n
[100 + 7.1] = [(344+v0)/(344+0)]100
107.1 = [(344+v0)/(344)]100
v0 = 24.42 m/s (Approx)
Answer:
Explanation:
Because as time passes, new experiments are being conducted with more powerful, advanced technology. This allows scientists to find new data which either causes scientific theories to change, reinforce pre-existing theories, or create new ones.
Answer:
Explanation:
According to newton's law , force between mass m₁ and m₂ at distance x is given by the following expression
F = G m₁m₂ / x²
differentiating F with respect to x , we have
dF / d x = ₋2G m₁m₂ / x³ .
Rate of reduction of force ∝ 1 / x³
