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statuscvo [17]
3 years ago
10

A particular radiograph was produced using 6 mAs and 110 kVp with an 8:1 ratio grid. The radiograph is to be repeated using a 16

:1 ratio grid. What should be the new mAs?
(A) 3 mAs
(B) 6 mAs
(C) 9 mAs
(D) 12 mAs
Physics
1 answer:
Orlov [11]3 years ago
6 0

Answer:

(C) 9 mAs

Explanation:

The computation of the new mAs is shown below:

Let us assume the New mAs be x

For adjusting the factors of exposure basically we compared the old one with the new one i.e. presented below:

6 ÷ x = 4 ÷ 6

where

6 = old mAs

4 = old grid factor

x = new mas

6 = new grid factor

Now solve this above equation with the help of cross multiplication

4x = 36

x = 9 mAs

Here we used the 16:1 ratio grid

Hence, the correct option is C. 9 mAs

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How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57×10−21 n
hichkok12 [17]

Answer:

891 excess electrons must be present on each sphere

Explanation:

One Charge = q1 = q

Force = F = 4.57*10^-21 N  

Other charge = q2 =q

Distance = r = 20 cm = 0.2 m  

permittivity of free space = eo =8.854×10−12 C^2/ (N.m^2)  

Using Coulomb's law,

F=[1/4pieo]q1q2/r^2

F = [1/4pieo]q^2 / r^2

q^2 =F [4pieo]r^2

q =  r*sq rt F[4pieo]

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q = 1.42614*10^ -16 C

number of electrons = n = q/e=1.42614*10^ -16 /1.6*10^-19

n =891

 891 excess electrons must be present on each sphere  

5 0
3 years ago
A sports car has an average acceleration of 5.81 m/s2. How long does it take for the car to reach 60.0 mi/h, if it starts from r
Aleks04 [339]

Answer:

  4.617 s

Explanation:

The speed of 60 mi/h can be converted to m/s:

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The relationship between speed and acceleration is ...

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It will take the car 4.617 seconds to reach 60 mi/h starting from rest.

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Baryon number is +1 on the left side of the equation, 0 on the

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<h3>How do you determine whether a baryon number is conserved?</h3>

  • According to the law of conservation of baryon number, the sum of the baryon numbers of all incoming particles equals the sum of the baryon numbers of all particles produced by the reaction. Energy, and so on, are conserved even if the incoming proton has sufficient energy and charge.
<h3>What is Baryon Number</h3>
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To learn more about Baryon Number refer to

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