Step-by-step explanation:
Let y1 and y2 be (e^x)/2, and (xe^x)/2 respectively.
The Wronskian of them functions be
W = (y1y2' - y1'y2)
y1 = (e^x)/2 = y1'
y2 = (xe^x)/2
y2' = (1/2)(x + 1)e^x
W = (1/4)(x + 1)e^(2x) - (1/4)xe^(2x)
= (1/4)(x + 1 - x)e^(2x)
W = (1/4)e^(2x)
Since the Wronskian ≠ 0, we conclude that functions are linearly independent, and hence, form a set of fundamental solutions.
Answer:
Step-by-step explanation:
2 to the 100 power = 1.2676506002 × 10 to the 30 power.
Rule: Negate x. (-x,y)
f(x)=g(-x)
f(x) 5x+8
g(x) = -5x+8
You will need 252 mL of pure water to obtain 0.25 mL of the desired 25% solution.
If we add X amount of water to the solution, the total amount of solution is 375+X.
And that must be 25%.
<h3>
What is the amount of solute in the current solution?</h3>
The amount of solute in the current amount of solution is
0.6(375)=225.
That amount won't change by adding water.
So we set up the equation so that the amount of solute divided by the new total amount of solution equals 25%.
225/(375+X)=0.25
cross multiply and solve
225/0.25=(375+X)
900-375=X
X=525
The pure water will you need to add to obtain the desired solution is 525.
Then we check 225/(375+525)=0.25.
To learn more about the mixture problem visit:
brainly.com/question/24647756
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