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11111nata11111 [884]
3 years ago
15

Solve for x.

Mathematics
1 answer:
Norma-Jean [14]3 years ago
6 0
1. x= 8

2. x=2

3. x=-9

4. x=4

5. x= -5

6. x=16

7 x=0

8: x=-3

Hope this helps!
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For an outdoor concert by the city​ orchestra, concert organizers estimate that 19 comma 000 people will attend if it is not rai
Amiraneli [1.4K]

Answer:

14,800 people are expected to attend the concert

Step-by-step explanation:

In this question, we are tasked with calculating the expected number of people that will attend a concert on a particular day.

The key to answering this question is to multiply the individual probabilities of the two events by the expected number of people

Mathematically, what we obtain is the following;

The expected number of people at the concert = (probability of raining × expected number of people when it rains) + (probability of not raining × Expected number of people when it does not rain)

From the question, we identify that;

Probability of raining = 30% = 30/100 = 0.3

Probability of not raining = 1-probability of raining = 1-0.3 = 0.7

Expected number of people when it rains = 5,000

Expected number of people when there is no rain = 19,000

we plus these vales into the equation we have;

The expected number of people at the concert =( 0.3 × 5,000) + (0.7 × 19,000) = 1,500 + 13,300 = 14,800 people

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3 years ago
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tankabanditka [31]

Answer:

\large{YES}\ \dfrac{BC}{YZ}=\dfrac{AC}{XY}=\dfrac{AB}{XZ}=\dfrac{2}{1}\\\\\text{and}\ \angle B\cong\angle Z,\ \angle C\cong\angle Y,\ \angle A\cong\angle X

Step-by-step explanation:

BC\to ZY\\AB\to XZ\\AC\to XY\\\angle A\to\angle X\\\angle B\to\angle Z\\\angle C\to\angle Y

\text{We have:}\\\\\triangle ABC:\ AB=20,\ BC=12,\ AC=18\\\triangle XZY:\ XZ=10,\ YZ=6,\ XY=9\\\\\text{check the ratio:}\\\\\dfrac{AB}{XZ}=\dfrac{20}{10}=2\\\\\dfrac{BC}{YZ}=\dfrac{12}{6}=2\\\\\dfrac{AC}{XY}=\dfrac{18}{9}=2\\\\\text{CORRECT :)}\\\\\angle B\cong\angle Z,\ \angle C\cong\angle Y\\\\\text{We know that: The sum of the acute angles in a right triangle is}\ 90^o.\\\\m\angle B+m\angle A=90^o\ \text{and}\ m\angle Z+m\angle X=90^o

\text{We know}\ m\angle B=m\angle Z\to \ m\angle A=m\angle X.\\\text{therefore}\ \angle A\cong\angle X

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