All categories

3 years ago

The length of a rectangular room is 5 feet more than its width. The perimeter of the room is

Mathematics

1 answer:

Roman55 [17]3 years ago

5 0

Answer:

$\displaystyle 39 = W \\ 44 = L$

Step-by-step explanation:

{L = W + 5

{166 = 2L + 2W

166 = 2[W + 5] + 2W

166 = 2W + 10 + 2W

166 = 10 + 4W

- 10 - 10

___________

$\displaystyle \frac{156}{4} = \frac{4W}{4}$

$\displaystyle 39 = W$ [Plug this back into both equations above to get the length of 44 feet; $\displaystyle 44 = L$

I am joyous to assist you anytime.

You might be interested in

The area of the square is 100 square centimeters. What is the area of the circle?

swat32

Answer:

Since the question is incomplete, see the figure attached and the explanation below.

Explanation:

Since the figure is missing, I enclose the figure of a square inscribed in a circle.

Since the <em>area of a square</em> is the side length squared, you can determine the side length:

Area = (side length)²

100 cm² = (side lenght)²

$side\text{ }length=\sqrt{100cm^2}=10cm$

From the side length, you can find the diagonal of the square, which is equal to the diameter of the circle, using the Pythagorean theorem:

diagonal² = (10cm)² + (10cm)² = 2 × (10cm)²

$diagonal=\sqrt{2\times (10cm)^2}\\ \\ diagonal=10\sqrt{2} cm$

The area of the circle is π (radius)².

radius = diameter/2 = diagonal/2

$area= \pi \times (5\sqrt{2}cm)^2=50\pi cm^2$

6 0

3 years ago

GIVING Brainly TO CORRECT Answer

nalin [4]

Answer:

Step-by-step explanation:

25 + 17 + 38 + 11 + 24 = 115 / 5 = 23

3 0

3 years ago

Read 2 more answers

Use the chain rule calculate dw/dr , dw/ds and dw/dt

Liono4ka [1.6K]

Answer:

$\frac{dw}{dr} = \frac{8\cdot r}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ , $\frac{dw}{ds} = \frac{10\cdot s}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ , $\frac{dw}{dt} = -\frac{2\cdot t}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$

Step-by-step explanation:

We proceed to derive each expression by rule of chain. Let be $w = \ln (x+2\cdot y + 3\cdot z)$ , $x = r^{2}+t^{2}$ , $y = s^{2}-t^{2}$ and $z = r^{2}+s^{2}$ :

$\frac{dw}{dr} = \frac{\frac{dx}{dr}+2\cdot \frac{dy}{dr} +3\cdot \frac{dz}{dr} }{x+2\cdot y + 3\cdot z}$

$\frac{dx}{dr} = 2\cdot r$

$\frac{dy}{dr} = 0$

$\frac{dz}{dr} = 2\cdot r$

$\frac{dw}{dr} = \frac{8\cdot r}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}$

$\frac{dw}{dr} = \frac{8\cdot r}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ (1)

$\frac{dw}{ds} = \frac{\frac{dx}{ds}+2\cdot \frac{dy}{ds} +3\cdot \frac{dz}{ds} }{x+2\cdot y + 3\cdot z}$

$\frac{dx}{ds} = 0$

$\frac{dy}{ds} = 2\cdot s$

$\frac{dz}{ds} = 2\cdot s$

$\frac{dw}{ds} = \frac{10\cdot s}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}$

$\frac{dw}{ds} = \frac{10\cdot s}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ (2)

$\frac{dw}{dt} = \frac{\frac{dx}{dt}+2\cdot \frac{dy}{dt} +3\cdot \frac{dz}{dt} }{x+2\cdot y + 3\cdot z}$

$\frac{dx}{dt} = 2\cdot t$

$\frac{dy}{dt} = -2\cdot t$

$\frac{dz}{dt} = 0$

$\frac{dw}{dt} = -\frac{2\cdot t}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}$

$\frac{dw}{dt} = -\frac{2\cdot t}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ (3)

7 0

3 years ago

Three angles are in the ratio 2 : 3 : 5 The smallest angle is 50 degrees Work out the sizes of the other two angles

Oxana [17]

Since the smallest angle is 50 degrees, then divide 50 by 2 (because of the ratio) and you get 25. Now you can multiply 25 by 3 and 25 by 5 to get the remaining angles which would be 75 degrees and 125 degrees.

5 0

3 years ago

Select the property NOT used in the following

Fudgin [204]

(2 + a) = (a + 2) it's commutative property

(a + 2) - 7 = a + (2 - 7) it's associative property

2 - 7 = -5 it's subtraction

Answer: distributive property { a(b + c) = ab + ac }

5 0

3 years ago