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exis [7]
3 years ago
6

Graph the line with slope of 53 5/3 and goes through the point (2,1).

Mathematics
1 answer:
klasskru [66]3 years ago
5 0

Answer:

We kindly invite you to see the image attached for further details.

Step-by-step explanation:

From Analytical Geometry we get that linear functions can be found after knowing a point and its slope. The standard form of a linear function is represented by the following formula:

y =m\cdot x +b (Eq. 1)

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

m - Slope, dimensionless.

b - y-Intercept, dimensionless.

At first we need to calculate the y-Intercept, which is cleared within (Eq. 1):

b = y-m\cdot x

If we know that y = 1, x = 2 and m = \frac{5}{3}, then the y-Intercept of the linear function is:

b = 1-\left(\frac{5}{3} \right)\cdot (2)

b = -\frac{7}{3}

Line with a slope of \frac{5}{3} that goes through the point (2, 1) is represented by y = \frac{5}{3}\cdot x -\frac{7}{3}.

Lastly, we graph the line by using a plotting software (i.e. Desmos), whose result is included below as attachment.

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Find the area of the surface the part of the plane y=x^2 y^2 cylinder x^2 z^2=16
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S=∬√1+(y)2+(x)2dAS=∬√1+x2+y2dA

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brainly.com/question/22972014

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