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Anvisha [2.4K]
3 years ago
14

An athlete's speed on her bike is 14mph faster than her average speed running. She can bike 31.5 miles in the same time that it

takes her to run 10.5 miles. Find her average speed running and her average speed biking.
Mathematics
1 answer:
scoundrel [369]3 years ago
7 0
You would cross multiply.
14 over 31.5
and X over 10.5
10.5 times 14 is 147
divide that by 31.5 which is 4 1/3
and that is how fast she can run
4 1/3 mph
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Step-by-step explanation:

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6 0
2 years ago
Two different weight loss programs are being compared to determine their effectiveness. Ten men were assigned to each program (t
True [87]

Answer:

WE reject the Null and conclude that one of the drug is more effective than the other.

Step-by-step explanation:

Given :

Diet 1 3.4 10.9 2.8 7.8 0.9 5.2 2.5 10.5 7.1 7.5

Diet 2 11.9 13.1 11.6 6.8 6.8 8.8 12.5 8.6 17.5 10.3

This is a matched pair sample :

The hypothesis :

H0 : μd = 0

H1 : μd ≠ 0

Hence, we intun the difference between the two groups of value :

Difference, d = -8.9,-2.2,-8.8,1,-5.9,-3.6,-10,1.9,-10.4,-2.8

The test statistic :

dbar ÷ (Sd/√n)

dbar = mean of difference = Σd / n = - 49.7 / 10 = - 4.97

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3 years ago
A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
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Given: f(x) = \frac{1}{x-2}

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f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

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B.

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Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



8 0
3 years ago
Math help please =)
a_sh-v [17]
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7 0
3 years ago
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Answer:

Step-by-step explanation:

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