Answer:
:0
Step-by-step explanation:
I am doing a quiz at the moment that is kind of like that 0.0
And unfortunatly I do not know the answer to that. I am so sorry
Answer:
Correct option: A
Step-by-step explanation:
The angle BDC inscribe the arc mBC, so we have that:
mBDC = (1/2) * mBC
mBDC = (1/2) * 118 = 59°
From the secants relation in a circle, we have that:
mA = (1/2) * (mBC - mDE)
35 = (1/2) * (118 - mDE)
70 = 118 - mDE
mDE = 48°
The sum of the arcs is 360°, so we have:
mBC + mCD + mDE + mBE = 360
118 + mCD + 48 + 76 = 360
mCD = 360 - 118 - 48 - 76 = 118°
The angle mCBD inscribes the arc mCD, so we have:
mCBD = (1/2) * mCD = (1/2) * 118 = 59°
The angles mCBD and mBDC are equal, so the triangle is isosceles.
Correct option: A
Answer:
Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360
.</u>
The option is
4. 270≤Ф≤360
Step-by-step explanation:
When the terminal arm of an angle starts from the x-axis in the anticlockwise direction then the angles are always positive angles.
For Example.
Quadrant I - 0 to 90°
Quadrant II - 90° to 180°
Quadrant III - 180° to 270°
Quadrant IV - 270° to 360° ( 4. 270≤Ф≤360 )
Hence,Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360
.</u>
When the terminal arm of an angle starts from the x-axis in the clockwise direction than the angles are negative angles.
Quadrant IV - 0° to -90°
Quadrant III - - 90° to -180°
Quadrant II - -180° to -270°
Quadrant I - -270° to -360°
Answer:
20%
Step-by-step explanation:
400/2000=0.2
0.2*100=20
