Answer:
25%
Explanation:
The female with brown teeth had a father with normal teeth. Since normal teeth is a recessive trait, the father would have been homozygous recessive for the trait and would have transmitted one recessive allele to the female. Therefore, the female is heterozygous dominant for brown teeth.
Let's assume that the allele for brown teeth is X^B while the one for normal teeth is X^b. The genotype of heterozygous dominant female would be X^BX^b and that of the male with normal teeth would be X^bY.
A cross between X^BX^b and X^bY gives progeny in following phenotype ratio= 1/4 daughter with brown teeth: 1/4 daughter with normal teeth: 1/4 son with brown teeth: 1/4 son with normal teeth. Therefore, the probability of having a daughter with brown teeth is = 25%
The answer is pilus. This structure joins two bacteria of same species and allow exchange of genetic material in a process called horizontal gene transfer (conjugation). The plasmid of one of the bacteria (the mobile plasmid) is nicked once and the strand moves through the pillus to the other bacteria. It combines with the other plasmid or chromosome to for recombinant dna.
The lac repressor prevents the lac genes in the DNA of E. coli from being expressed most of the time. The answer to your question is A. I hope this is the answer that you are looking for and it comes to your help.
Name three plants like trees, sunflowers, and grass
<span>B: within hurricanes that come from Canada</span>