I think it is erosion (2) because erosion removes soil, rock, and dissolved material.
Answer:
6,25%
Explanation:
Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:
Parents: Aa X Aa
Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)
Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:
A x A = 1/4 = 25%
A x a = 1/4 = 25%
a x A = 1/4 = 25%
a x a = 1/4 = 25%
The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:
1/4 × 1/4 = 1/16 = 0.0625 = 6.25%
It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.
Answer:
The rectum is located at the "left lower portion" of the abdominal pelvic region.
Explanation:
The rectum is present at the left lower portion of the abdominal area which gives partial view of the small intestine. Descending to it a sigmoid colon, rectum, left ureter and urinary bladder is present. The diameter of the rectum is like a sigmoid colon near the onset. However, it is bigger at the anus as it forms the rectal ampulla near it. The main function of the rectal ampulla is to store the feces for temporary period. The size of the rectum is 8 inch and it has connected the colon as well as the anus.
