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oksano4ka [1.4K]
3 years ago
14

The box plots below show the average daily temperatures in January and December for a U.S.

Mathematics
1 answer:
Marysya12 [62]3 years ago
3 0

Answer:

The answer is C

Step-by-step explanation:

Took the test!

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X If $7500 was compounded annually for 8 years at a rate of .23% how much will it be
Ann [662]

Answer:

$7639.12

Step-by-step explanation:

We use the compound formula for accrued value (A) for a principal P deposited at an annual rate "r" over t years

A = P (1+r)^t

In our case, with the given information, the formula becomes:

A = P (1+r)^t\\A=7500 \,(1.0023)^8\\A = 7639.11602

which rounded to the nearest cent gives:  $7639.12

4 0
3 years ago
Craig has a job waiting tables where he earns $3.15 per hour plus tips. Craig earned $74.67 in tips during his shift yesterday.
oksano4ka [1.4K]

Answer:

3.15x-79.48

i think c:

3 0
3 years ago
Given that F(x) = x 2 + 2, evaluate F(1) + F(5).
Igoryamba

Answer:

F(1)= (1)2 + 2

          2+2

           =4

F(5)= (5)2 + 2

          10+2

           =12

F(1) + F(5) = 12+4

            =16

Step-by-step explanation:

:D

8 0
3 years ago
A circle is inside a square as shown.
Harrizon [31]

Answer:

9.76m²

Step-by-step explanation:

The area of the square is

Area =  {s}^{2}

where s=8m is the side length.

This means that:

Area =  {8}^{2}  = 64 {m}^{2}

The area of a circle is

Area = \pi \:  {r}^{2}

From the diagram, the diameter is 8m.

This means that the radius is

r =  \frac{8}{2}  = 4m

The area of the circle then becomes,

Area =3.14\:  \times  {4}^{2}  = 3.14 \times 16

Area = 50.24 {m}^{2}

The area of shaded region is area of square minus area of circle.

Area \: of \: shaded \: region = 64 - 50.24 = 9.76 {m}^{2}

8 0
4 years ago
Devin runs a factory that makes Blu-ray players. Each R80 takes 9 ounces of plastic and 2 ounces of metal. Each G150 requires 3
alexira [117]

9514 1404 393

Answer:

  R80: 12

  G150: 54

  Best Profit: $582

Step-by-step explanation:

Let x and y represent the numbers of R80 and G150 players, respectively. The constraints of the problem are ...

  0 ≤ x ≤ 18 . . . . . a maximum of 18 R80 can be built

  0 ≤ y . . . . . . . . . only non-negative numbers can be built

  9x +3y ≤ 270 . . . . ounces of plastic used cannot exceed 270

  2x +6y ≤ 348 . . . . ounces of metal used cannot exceed 348

The objective is to maximize the profit function ...

  P(x, y) = 8x +9y

The attached graph shows profit is a maximum of $582 per week when 12 R80 players and 54 G150 players are produced.

_____

Since the maximum profit is at a value of x less than 18, we didn't bother to graph that constraint.

5 0
3 years ago
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