A complete program with the method ShowCar:
import java.util.Scanner; // header file
public class ShowChar
{
public static void main(String[] args)
{
String lnOfText;
int i;
Scanner input = new Scanner(System.in);
System.out.print("Enter a line of text:");
lnOfText = input.nextLine();
System.out.print(" Enter your index: ");
i = input.nextInt();
show_Char(lnOfText,i);
}
public static void show_Char(String str_a, int i)
{
System.out.print(str_a.charAt(i));
}
}
In this program, both the inputs ie. a sentence or line of text as well as the index position is obtained. A method is written to find the string at that particular position. Finally the method prints that character at the particular index.
No I don’t know what are you saying can you explain or I’m here for points heheheh and Java is written in any way
Answer:
Option (B) is correct answer.
Explanation:
In this whole world, any person needs to do the task because of some profits. If there is a task with more points and if it is easy then it needs to be executed first.
Here in this question, story 2 is an easy task and gives more money, so that is to be executed first. Story 4 also gives more money but it is not easy so no one grantee to complete the task.
Hence option b is the correct answer. while the other option is not because--
- Option "a" states about story 1, which is easy to complete but can not provide any type of value or money. So why anyone complete that task first which does not gives any types of profits.
- Option c states about story 3, which is not easy to complete and also does not give any profits. So do not need to complete that task first which does not provide any profits and also that is difficult.
- Option d states about story 4, which is not easy to complete but gives a lot of points. But there is no grantee that the task can complete in time. so no one needs to complete the risky task in the first order.
Hence the team member needs to execute the task in the following order--
- Story 2
- Story 4
- Story 1 and then
- Story 3
